如何合并连续的子数组，这些子数组中包含相同的数据？

Question

我有这个数组：

$opening_hours = array(
  'Monday' => array('09:00', '17:00'),
  'Tuesday' => array('09:00', '17:00'),
  'Wednesday' => array('08:00', '13:00'), 
  'Thursday' => array('09:00', '17:00'),
  'Friday' => array('09:00', '17:00'),
  'Saturday' => array('10:00', '16:00'),
  'Sunday' => array('Closed'),
);

我需要以某种方式将这些营业时间合并到数组中，该数组应如下所示：

$merged_opening_hours = array(
  'Monday - Tuesday' => array('09:00', '17:00'),
  'Wednesday' => array('08:00', '13:00'),
  'Thursday - Friday' => array('09:00', '17:00'),
  'Saturday' => array('10:00', '16:00');
  'Sunday' => array('Closed'),
);

你有什么想法？

- David

---

@FrancescoAbeni 我尝试循环遍历$opening_hours数组，并检查数组的下一个元素是否与当前元素相同，但不知何故这并没有起作用。Rizier123用解释完全做到了我需要的。 - David

Answer 1

这应该适用于您：

基本上，您只需循环遍历整个数组并检查下一个元素是否仍然已设置且当前数组与下一个数组相同（这意味着它们具有相同的小时数）。如果是，则执行此操作，直到while循环返回false。代码如下：

$DayAmountOfConsecutiveSameHours = 1;
while(isset($arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]) && 
     ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]]))
    $DayAmountOfConsecutiveSameHours++;

如果有一个以上的条目，您可以创建从一个日期到另一个日期的范围。以下是代码:

if($DayAmountOfConsecutiveSameHours > 1)
    $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];

如果你只有1天，时间也相同，那么只需将它添加到结果数组中，代码如下：

：

else
    $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

根据您跳过相同小时数的天数来确定下一个数组元素。代码如下：

$dayCount += ($DayAmountOfConsecutiveSameHours - 1);

完整代码：

<?php

    $opening_hours = [
            "Monday" => ["09:00", "17:00"],
            "Tuesday" => ["09:00", "17:00"],
            "Wednesday" => ["08:00", "13:00"], 
            "Thursday" => ["09:00", "17:00"],
            "Friday" => ["09:00", "17:00"],
            "Saturday" => ["10:00", "16:00"],
            "Sunday" => ["Closed"],
        ];


    $amountOfDays = count($opening_hours);
    $arrayKeys = array_keys($opening_hours);

    for($dayCount = 0; $dayCount < $amountOfDays; $dayCount++) {
        $DayAmountOfConsecutiveSameHours = 1;
        while(isset($arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]) && ($opening_hours[$arrayKeys[$dayCount]] === $opening_hours[$arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours)]]))
            $DayAmountOfConsecutiveSameHours++;

        if($DayAmountOfConsecutiveSameHours > 1)
            $result[$arrayKeys[$dayCount] . " - " . $arrayKeys[($dayCount+$DayAmountOfConsecutiveSameHours-1)]] = $opening_hours[$arrayKeys[$dayCount]];
        else
            $result[$arrayKeys[$dayCount]] = $opening_hours[$arrayKeys[$dayCount]];

        $dayCount += ($DayAmountOfConsecutiveSameHours - 1);
    }

    print_r($result);

?>

输出：

Array
(
    [Monday - Tuesday] => Array
        (
            [0] => 09:00
            [1] => 17:00
        )

    [Wednesday] => Array
        (
            [0] => 08:00
            [1] => 13:00
        )

    [Thursday - Friday] => Array
        (
            [0] => 09:00
            [1] => 17:00
        )

    [Saturday] => Array
        (
            [0] => 10:00
            [1] => 16:00
        )

    [Sunday] => Array
        (
            [0] => Closed
        )

)

演示

- Rizier123

---

感谢您的解释和整个函数。它确实像应该的那样工作。在提出这个问题之前，我已经开始比较数组的下一个元素与当前元素，在我的情况下它没有起作用。再次感谢。 - David

@David 更新了我的答案并将一切都简化了一些。希望这样更容易理解。 - Rizier123