以下是我的随机生成代码:
int monstername;
monstername = rand() % 3;
但我希望用C语言实现以下需求:输出结果中0占70%,1占20%,2占10%。请问如何实现?
int monstername;
int random_var = rand() % 10;
if(random_var < 7) {
// 0-70%
monstername = 0;
}
else if(random_var < 9) {
// 70-90% here
monstername = 1;
}
else {
// 90-100% here
monstername = 2;
}
尝试
int monstername;
int rn = rand();
if (rn < 0.7*RAND_MAX)
monstername = 0;
else if (rn < 0.9*RAND_MAX)
monstername = 1;
else
monstername = 2;
int monstername;
int r = rand() % 10;
if (r < 7)
monstername = 0;
else if (r < 9)
monstername = 1;
else
monstername = 2;
arc4random_uniform(3)
而不是 rand(3)
。int weighted[10] = {0,1,0,0,1,0,0,2,0,0};
monstername = weighted[rnd() % 10];