显然，OpenURL在iOS 10中已被弃用。有没有人有关于为什么要这样做的文档或者可以解释接下来该怎么做？我已经在苹果网站上查找了一些与OpenURL相关的东西，而现在他们建议使用以下内容：
所以显然，OpenURL在iOS 10中已经被弃用。是否有关于此举原因的文档或者有人能解释下一步该怎么做呢？我已经在苹果网站上找到了一些关于OpenURL的东西，他们建议现在使用以下内容：
UIApplication.shared().open(url: URL, options: [String: AnyObject], completionHandler: ((Bool) -> Void)?)
有人有证据表明这是在Swift 3.0中使用OpenURL的新方式吗？此外，options:和completionHandler:参数分别应使用哪些值？
Swift 3+：
func open(scheme: String) {
if let url = URL(string: scheme) {
if #available(iOS 10, *) {
UIApplication.shared.open(url, options: [:],
completionHandler: {
(success) in
print("Open \(scheme): \(success)")
})
} else {
let success = UIApplication.shared.openURL(url)
print("Open \(scheme): \(success)")
}
}
}
使用方法：
open(scheme: "tweetbot://timeline")
一种快速修复方法：
// Objective-C
UIApplication *application = [UIApplication sharedApplication];
[application openURL:URL options:@{} completionHandler:nil];
// Swift
UIApplication.shared.open(url, options: [:], completionHandler: nil)
一个完整的答案：
http://useyourloaf.com/blog/openurl-deprecated-in-ios10/
Credits: Keith Harrison (useyourloaf.com)
一个空的选项字典将会导致与openUrl相同的行为。
否则：
+-------------------------------------------------+----------------------------------------------------------------------------------------------------------------------------------------------+
| UIApplicationOpenURLOptionsSourceApplicationKey | NSString containing the bundle ID of the originating application |
+-------------------------------------------------+----------------------------------------------------------------------------------------------------------------------------------------------+
| UIApplicationOpenURLOptionsAnnotationKey | property-list typed object corresponding to what the originating application passed in UIDocumentInteractionController's annotation property |
+-------------------------------------------------+----------------------------------------------------------------------------------------------------------------------------------------------+
| UIApplicationOpenURLOptionsOpenInPlaceKey | bool NSNumber, set to YES if the file needs to be copied before use |
+-------------------------------------------------+----------------------------------------------------------------------------------------------------------------------------------------------+
来自UIApplication.h
// Options are specified in the section below for openURL options. An empty options dictionary will result in the same
// behavior as the older openURL call, aside from the fact that this is asynchronous and calls the completion handler rather
// than returning a result.
// The completion handler is called on the main queue.
- (void)openURL:(NSURL*)url options:(NSDictionary<NSString *, id> *)options completionHandler:(void (^ __nullable)(BOOL success))completion NS_AVAILABLE_IOS(10_0) NS_EXTENSION_UNAVAILABLE_IOS("");
UIKIT_EXTERN UIApplicationOpenURLOptionsKey const UIApplicationOpenURLOptionsSourceApplicationKey NS_SWIFT_NAME(sourceApplication) NS_AVAILABLE_IOS(9_0); // value is an NSString containing the bundle ID of the originating application
UIKIT_EXTERN UIApplicationOpenURLOptionsKey const UIApplicationOpenURLOptionsAnnotationKey NS_SWIFT_NAME(annotation) NS_AVAILABLE_IOS(9_0); // value is a property-list typed object corresponding to what the originating application passed in UIDocumentInteractionController's annotation property
UIKIT_EXTERN UIApplicationOpenURLOptionsKey const UIApplicationOpenURLOptionsOpenInPlaceKey NS_SWIFT_NAME(openInPlace) NS_AVAILABLE_IOS(9_0); // value is a bool NSNumber, set to YES if the file needs to be copied before use
openURL:options:completionHandler:是我们应该使用的新函数吗？还是这就是我在问题中提出的建议？在这种情况下，您仍然需要使用UIApplication.shared()...。 - KSigWyatt加载网址之前需要进行一些检查。请先检查以下代码：
if ([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:@"https://www.gmail.com"]]){
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"https://www.gmail.com"] options:@{} completionHandler:^(BOOL success) {
//completion codes here
}];
}
let actual:
[String: AnyObject] = ["xxx key": "xxx value" as AnyObject, "yyy key": "yyy value" as AnyObject]
UIApplication.shared.open(URL(string: "http:google.com")!, options: actual, completionHandler: {(true) -> Swift.Void in
print("Refresh")
})
其中 xxx 和 yyy 是您想要打印或留空的任何字符串。
你可以使用函数打开设置：
func showAlert(title:String, message:String){
let alert = UIAlertController(title: title,
message: message,
preferredStyle: UIAlertController.Style.alert)
let okAction = UIAlertAction(title: "OK", style: .cancel, handler: nil)
alert.addAction(okAction)
let settingsAction = UIAlertAction(title: "Settings", style: .default, handler: { _ in
// Take the user to Settings app to possibly change permission.
guard let settingsUrl = URL(string: UIApplication.openSettingsURLString) else { return }
if UIApplication.shared.canOpenURL(settingsUrl) {
if #available(iOS 10.0, *) {
UIApplication.shared.open(settingsUrl, completionHandler: { (success) in
// Finished opening URL
})
} else {
// Fallback on earlier versions
UIApplication.shared.openURL(settingsUrl)
}
}
})
alert.addAction(settingsAction)
present(alert, animated: true, completion: nil)
}
按照下面的方式调用此函数
showAlert(title: "Unable to access the Photos", message: "To enable access, go to Settings > Privacy > Photos and turn on Photos access for this app.")