安卓：单击时的上下文菜单

Question

我有一个继承自ListActivity的Intent。在我的onCreate方法中，当我填充了列表适配器后，我使用registerForContextMenu(getListView());来注册上下文菜单。

现在它正常工作并且上下文菜单具有其原始功能，即：一旦我点击并按住某个项目，上下文菜单就会打开。

我能否在单击（而不必按住列表）时打开上下文菜单？

非常感谢您的帮助。

- Adnan

Answer 1

以下是另一种更简单的在单击时显示上下文菜单的方法。

private void addOnClickListener()
{
    contactList.setOnItemClickListener(new AdapterView.OnItemClickListener()
    {
        public void onItemClick(AdapterView<?> parent, View view, int position, long id)
        {
              view.showContextMenu();
        }
    })
}

将contactList替换为您的ListView，并确保在ListView初始化后调用此方法。

- Pawan Maheshwari

---

太棒了。这也可以完美地与片段类一起使用。谢谢 :) - caligari

Answer 2

在单击项时调用activity.openContextMenu(l)以打开上下文菜单，在长按时调用activity.closeContextMenu()

示例

import android.app.Activity;
import android.app.ListActivity;
import android.content.res.Configuration;
import android.os.Bundle;
import android.view.ContextMenu;
import android.view.ContextMenu.ContextMenuInfo;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemLongClickListener;
import android.widget.ArrayAdapter;
import android.widget.ListView;

public class MyListView extends ListActivity implements OnItemLongClickListener {
    /** Called when the activity is first created. */
    Activity activity = null;
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        activity = this;


        ArrayAdapter arrayAdapter = new ArrayAdapter<String>(this,
                android.R.layout.simple_list_item_1, PENS);
        setListAdapter(arrayAdapter);

        getListView().setTextFilterEnabled(true);
        ListView lv = getListView();
        this.registerForContextMenu(lv);

        lv.setOnItemLongClickListener(this);


    }

    @Override
    public void onConfigurationChanged(Configuration newConfig) {
        // TODO Auto-generated method stub

        super.onConfigurationChanged(newConfig);
        System.out.println("...11configuration is changed...");
    }

    static final String[] PENS = new String[]{
        "MONT Blanc",
        "Gucci",
        "Parker",
        "Sailor",
        "Porsche Design",
        "item1",
        "item2",
        "item3",
        "item4",
        "item5",
        "item6",
        "item7",
        "item8",
        "item9",
        "item10",
        "item11"



    };



    protected void onListItemClick(ListView l, View v, int position, long id) {
        super.onListItemClick(l, v, position, id);

        activity.openContextMenu(l);
        System.out.println("...context is called");

    }




    @Override
    public void onCreateContextMenu(ContextMenu menu, View v,
            ContextMenuInfo menuInfo) {
        // TODO Auto-generated method stub
        System.out.println("...on create context menu...");
        super.onCreateContextMenu(menu, v, menuInfo);
    }

    public boolean onItemLongClick(AdapterView<?> arg0, View arg1, int arg2,
            long arg3) {
        System.out.println("...on long click close context menu...");
        activity.closeContextMenu();
        // TODO Auto-generated method stub

        return false;
    }

- Sunil Kumar Sahoo

---

如何展开自定义上下文菜单？ - undefined

Answer 3

我觉得它并没有很顺畅的运行。调用 openContextMenu(l) 会导致 item.getMenuInfo() 为空（在方法 onContextItemSelected(MenuItem item) 内）。

你应该调用 l.showContextMenuForChild(v) 而不是 openContextMenu(l)。

- sancho21

---

showContextMenu将进一步调用showContextMenuForChild。 - codebased

Answer 4

这份工作完美无缺......

    listmp3 = (ListView) findViewById(R.id.results_mp3);
    registerForContextMenu(listmp3);

    listmp3.setOnItemClickListener(new AdapterView.OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
            listmp3.showContextMenuForChild(view);
        }
    });

- jpmaster