在下面的子程序中,
@{$violated{$desc}||=[]}
数组是什么意思?尽管我理解@{$violated{$desc}}
是由$violated{$desc}
引用的匿名数组。sub not_in_file_ok {
my ($filename, %regex) = @_;
open( my $fh, '<', $filename ) or die "couldn't open $filename for reading: $!";
my %violated;
while (my $line = <$fh>) {
while (my ($desc, $regex) = each %regex) {
if ($line =~ $regex) {
push @{$violated{$desc}||=[]}, $.;
}
}
}
if (%violated) {
fail("$filename contains boilerplate text");
diag "$_ appears on lines @{$violated{$_}}" for keys %violated;
} else {
pass("$filename contains no boilerplate text");
}
}
||=
,[]
返回数组引用。如果清晰度很重要,应该写成$violated{$desc} ||= []; push @{$violated{$desc}}, $.;
。 - mpapec