似乎无法从securityinfo
字段传递任何内容。
for ($k = 1; $k < $fieldscnt; $k++)
{
$selectsecurityname = mysql_query("SELECT `security name` FROM securityinfo WHERE symbol = '$symbol[$k]'") or die(mysql_error());
$securityname = mysql_fetch_array($selectsecurityname);
$sym = $symbol[$k]
echo "<td>$securityname[$sym]</td>";
}
基本上,我想要查找在symbol
字段中有匹配的行,然后返回同一行中securityinfo
字段的值。