溢出菜单中的自定义菜单项

Question

溢出菜单中的自定义菜单项

4

我应该如何制作一个自定义菜单项，就像附图中菜单的第一行一样（Google Chrome应用程序的屏幕截图）？

我尝试在onCreateOptionsMenu中使用下面的代码，其中R.layout.menu_top_row是第一行的布局。但是在我的情况下只显示了一个空白行？我能够显示其余选项，但无法显示第一行。

View child = getLayoutInflater().inflate(R.layout.menu_top_row, null);
    MenuItem menuItem=menu.add("");
    menuItem.setActionView(child);

- Diffy

1个回答

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- Andrew Orobator · Accepted Answer

这个stack overflow答案中提到：

PopupMenu 用于显示菜单，但是没有很好的方法来自定义菜单项的外观。如果您想要更灵活的东西，那么您的答案是ListPopupWindow。

private static final String TITLE = "title";
private static final String ICON = "icon";

private List<HashMap<String, Object>> data = new ArrayList<HashMap<String, Object>>();

// Use this to add items to the list that the ListPopupWindow will use
private void addItem(String title, int iconResourceId) {
    HashMap<String, Object> map = new HashMap<String, Object>();
    map.put(TITLE, title);
    map.put(ICON, iconResourceId);
    data.add(map);
}

// Call this when you want to show the ListPopupWindow
private void showListMenu(View anchor) {
    ListPopupWindow popupWindow = new ListPopupWindow(this);

    ListAdapter adapter = new SimpleAdapter(
            this,
            data,
            android.R.layout.activity_list_item, // You may want to use your own cool layout
            new String[] {TITLE, ICON}, // These are just the keys that the data uses
            new int[] {android.R.id.text1, android.R.id.icon}); // The view ids to map the data to


    popupWindow.setAnchorView(anchor);
    popupWindow.setAdapter(adapter);
    popupWindow.setWidth(400); // note: don't use pixels, use a dimen resource
    popupWindow.setOnItemClickListener(myListener); // the callback for when a list item is selected
    popupWindow.show();
}