UISegmentedControl选中的分段颜色

Question

UISegmentedControl选中的分段颜色

73

有没有办法自定义UISegmentedControl中选定段的颜色？

我发现了segmentedController.tintColor属性，它允许我自定义整个分段控件的颜色。问题在于，当我为tintColor属性选择明亮的颜色时，选定的段几乎无法被识别（它的颜色与其余分段控件的颜色几乎相同，因此很难区分选定和未选定的段）。所以我不能使用任何好看的明亮颜色作为分段控制的颜色。解决方案是一些单独的选定段颜色的属性，但我找不到这个属性。有人解决了这个问题吗？

- Mike

理论上，此组件旨在防止此类情况发生。如果您选择背景颜色和色调颜色，则会为所选和未选中的内容交替显示。例如，如果您选择黑色背景和白色色调，则在选择其中一个时，它将以白色背景和黑色色调放置，反之亦然。 - jose920405

https://dev59.com/1lwZ5IYBdhLWcg3wROeN#55374590 - Lal Krishna

23个回答

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可以查看英文原文，
原文链接

- Barlow Tucker · Answer 1

我在iOS 7上遇到了这个问题，它与iOS 6不同。在iOS 7中，所选段的标签颜色与UISegementControl背景颜色相同。唯一改变它的方法是设置UISegmentControl的背景颜色。

segmentControl.backgroundColor = customColor;

- cacheflowe · Answer 2

不确定这个是否会被应用商店批准，但我编写了一个UISegmentedControl的子类，可以让您设置自定义的选中和未选中颜色。查看注释以获取更多信息：

http://uihacker.blogspot.com/2010/05/iphone-uisegmentedcontrol-custom-colors.html

- geekay · Answer 3

我想知道为什么没有人提到UIAppearanceProxy

苹果文档::

https://developer.apple.com/documentation/uikit/uisegmentedcontrol#1653545

示例代码：

    private class func applyUISegmentControlAppearance(){
    let apperance = UISegmentedControl.appearance()

    // Set Navigation bar Title colour
    let unselAttrib = [NSForegroundColorAttributeName:UIColor.yellow,
                                        NSFontAttributeName: UIFont.systemFont(ofSize: 15)]

    let selAttrib = [NSForegroundColorAttributeName:UIColor.red,
                     NSFontAttributeName: UIFont.boldSystemFont(ofSize: 15)]


    apperance.setTitleTextAttributes(unselAttrib, for: .normal)
    apperance.setTitleTextAttributes(selAttrib, for: .selected)
}

来自： 您可以在AppDelegate中调用此方法

application(_ application: UIApplication, willFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey : Any]? = nil) -> Bool

- RexMac66 · Answer 4

我发现可以使用与段相同索引的子视图上的标记，以便无论以任何顺序它们都能正确着色。

// In viewWillAppear set up the segmented control 

// then for 3 segments:  
self.navigationItem.titleView = segmentedControl;
//Order of subviews can change randomly!, so Tag them with same index as segment
[[[segmentedControl subviews]objectAtIndex:0]setTag:0]; 
[[[segmentedControl subviews]objectAtIndex:1]setTag:1];
[[[segmentedControl subviews]objectAtIndex:2]setTag:2];


// color follows the selected segment
- (IBAction)mySelector:(id)sender {
selector = [sender selectedSegmentIndex]
  for (id seg in [segmentedControl subviews]) {
    for (id label in [seg subviews]) {
        if ([seg tag] == selector){
            [seg setTintColor:selectedColor];
        } else {
            [seg setTintColor:nonSelectedColor];
        }
    }
  }
}

// in viewDidAppear for returning to the view
[segmentedControl setSelectedSegmentIndex:selector];
for (id seg in [segmentedControl subviews]) {
    for (id label in [seg subviews]) {
        if ([seg tag] == selector){
            [seg setTintColor:selectedColor];
        } else {
            [seg setTintColor:nonSelectedColor];
        }
    }
}

- Brandon O'Rourke · Answer 5

当我在不同的段之间切换时，前两个解决方案对我没有用。

我的解决方案是在我的视图控制器中处理段变更事件，然后每次更改段时调用此方法：

+ (void)setSegmentedControl:(UISegmentedControl *)segmentedControl 
              selectedColor:(UIColor *)selectedColor 
            deselectedColor:(UIColor *)deselectedColor
{
    for (int i = 0; i < segmentedControl.subviews.count; i++) 
    {
        id subView = [segmentedControl.subviews objectAtIndex:i];

        if ([subView isSelected])
            [subView setTintColor:selectedColor];
        else
            [subView setTintColor:deselectedColor];
    }    
}

- Alvin George · Answer 6

Try this solution.

        @IBAction func dashBoardSegmentValueChanged(sender: AnyObject) {
            switch dashBoardSegment.selectedSegmentIndex
            {
            case 0:     
                sender.subviews.last?.backgroundColor = UIColor.whiteColor()
                sender.subviews.first?.backgroundColor =  UIColor.clearColor()

                break;
            case 1:            
                sender.subviews.first?.backgroundColor =  UIColor.whiteColor()
                sender.subviews.last?.backgroundColor = UIColor.clearColor()
                break;
            default:
                break;
            }
        }

Note: Make sure you select one segment subview as initial selected for easiness. It works if you have two segment subviews.

- Ted · Answer 7

- (IBAction)segmentedControlValueChanged:(UISegmentedControl *)sender {
    for (int i = 0; i < sender.subviews.count; i++) {
        UIControl *component = [sender.subviews objectAtIndex:i];
        if ([component respondsToSelector:@selector(isSelected)]) {
            UIColor *selectedColor = [UIColor greenColor];
            UIColor *normalColor   = [UIColor blackColor];
            UIColor *tint = component.isSelected ? selectedColor : normalColor;
            [component setTintColor:tint];
        }
    }
}

- ICL1901 · Answer 8

我发现以上的答案非常有帮助。我正在使用分段控件来设置旋钮的精度。我综合了以上的答案，得出了以下代码：

-(void) viewDidLoad {

NSArray *segments = [NSArray arrayWithObjects:@"Course", @"Fine",nil];

[knob setPrecision:0.1]; // initial precision
// Set starting values

UISegmentedControl *segmentedControl = [[UISegmentedControl alloc] initWithItems:segments];

segmentedControl.segmentedControlStyle = UISegmentedControlStyleBar;
segmentedControl.frame = CGRectMake(120, 680, 228, 30);
[segmentedControl addTarget:self action:@selector(precisionSelect:) forControlEvents:UIControlEventValueChanged];
segmentedControl.momentary = YES;

[self.view addSubview:segmentedControl];
}   

- (void)precisionSelect:(UISegmentedControl*)sender
{   
    UIColor *tintcolor = [UIColor darkGrayColor];   
    if (sender.selectedSegmentIndex == 0) {
        [[sender.subviews objectAtIndex:0] setTintColor:nil];
        [[sender.subviews objectAtIndex:1] setTintColor:tintcolor];
    [knob setPrecision:0.1]; // Coarse
    } else {
        [[sender.subviews objectAtIndex:0] setTintColor:tintcolor];
        [[sender.subviews objectAtIndex:1] setTintColor:nil];
    [knob setPrecision:0.05]; // Fine
    }

}

希望这能帮助到其他人.. 对我来说，关键是能够使用以下代码重置未选择的索引：setTintColor:nil];

- scooter133 · Answer 9

您可以为每个段落设置标签，然后为标签设置TintColor：

#define kTagOffState 0
#define kTagOnState  2

#define UIColorFromRGB(rgbValue) [UIColor \
        colorWithRed:((float)((rgbValue & 0xFF0000) >> 16))/255.0 \
        green:((float)((rgbValue & 0xFF00) >> 8))/255.0 \
        blue:((float)(rgbValue & 0xFF))/255.0 alpha:1.0]

//usage     UIColor color = UIColorFromRGB(0xF7F7F7);

 UIColor onColor = UIColorFromRGB(0xF7F7F7);
 UIColor offColor = UIColorFromRGB(0x878787);

        [multiStateControl setTag:kTagOffState forSegmentAtIndex:0];
        [multiStateControl setTag:kTagOnState forSegmentAtIndex:1];
        [multiStateControl setTintColor:onColor forTag:kTagOnState];
        [multiStateControl setTintColor:offColor forTag:kTagOffState];

- Madhup Singh Yadav · Answer 10

要做您这样的事情，可能需要访问未记录的功能和黑客技巧，这肯定会让苹果很生气，这可能会导致您的应用被拒绝。

现在，解决方案在于使用另一种技巧，您可以使用两个按钮，并在单击它们时交换它们的图像。将按钮放得更靠近，并使用半分段控件的图像来产生分段控件的幻觉，这是我能为您提供的全部建议。

希望这有所帮助。

谢谢，

Madhup