我将会为您翻译以下内容:
感谢您的帮助:D
编辑:根据要求,附上我的views.py和urls.py代码
views.py
我正在尝试在遵循Django模板语言的HTML文件中使用变量从字典中获取值。Django模板语言不允许您使用变量作为键来访问字典,因此我决定使用Django过滤器来实现。然而,我一直收到“无效过滤器”错误,但我无法找出原因。
我的HTML文件:
<table class="table">
<tbody>
<tr>
<th scope="row">Username</th>
<th scope="row">Full Name</th>
<th scope="row">Points</th>
{% for subject in subjects %}
<th scope="row">{{ subject }}</th>
{% endfor %}
</tr>
{% for user in users %}
<tr>
<td>
<a href="{% url 'profile' username=user.username %}">{{ user.username }}</a>
</td>
<td>{{ user.first_name }} {{ user.last_name }}</td>
<td>{{ user.profile.points.total }}</td>
{% for subject in subjects %}
<td>{{ user.profile.points|keyvalue:subject }}</td>
{% endfor %}
</tr>
{% endfor %}
</tbody>
我的filter.py
from django import template
register = template.Library()
@register.filter
def keyvalue(dict, key):
return dict[key]
我的错误信息
TemplateSyntaxError at /leaderboard/
Invalid filter: 'keyvalue'
感谢您的帮助:D
编辑:根据要求,附上我的views.py和urls.py代码
views.py
def leaderboard(request):
global leaderboard_public
users = sorted(User.objects.all(), key=lambda t: t.profile.points['total'], reverse=True)
if request.method == "POST":
leaderboard_public = not leaderboard_public
return redirect(leaderboard)
subjects = list(Subject.objects.values('subject_name'))
subjects = [i['subject_name'] for i in subjects]
print(subjects)
return render(request, "leaderboard.html", {
"users": users,
"subjects": subjects,
# "leaderboard_public": leaderboard_public,
})
urls.py
from accounts import views as accountsViews
from puzzles import views as puzzlesViews
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^signup/$', accountsViews.signup_without_email, name="signup"),
url(r'^activate/(?P<uidb64>[0-9A-Za-z_\-]+)/(?P<token>[0-9A-Za-z]{1,13}-[0-9A-Za-z]{1,20})/$',
accountsViews.activate, name='activate'),
url(r'^logout/$', authViews.LogoutView.as_view(), name='logout'),
url(r'^login/$', authViews.LoginView.as_view(template_name='login.html'), name="login"),
# url(r'^puzzles/$', puzzlesViews.puzzles, name="puzzles"),
url(r'^puzzle/(?P<puzzleID>.+)/edit/$', puzzlesViews.editPuzzle, name="editPuzzle"),
url(r'^puzzle/(?P<puzzleID>.+)/$', puzzlesViews.puzzle, name="puzzle"),
url(r'^scheduled/$', puzzlesViews.scheduled, name="scheduled"),
url(r'^closed/$', puzzlesViews.closed, name="closed"),
url(r'^leaderboard/$', accountsViews.leaderboard, name="leaderboard"),
# url(r'^leaderboard/(?P<subject>.+)/$', accountsViews.leaderboard_subject, name="leaderboard"),
# url(r'^submissions/$', puzzlesViews.submissions, name="submissions"),
url(r'^profile/(?P<username>.+)/submissions$', puzzlesViews.submissions, name="submissions"),
url(r'^profile/(?P<username>.+)/edit/$', accountsViews.editProfile, name="editProfile"),
url(r'^profile/(?P<username>.+)/$', accountsViews.profile, name="profile"),
url(r'^create/$', puzzlesViews.create, name="create"),
# url(r'^$', views.home, name="home"),
url(r'^$', puzzlesViews.puzzles, name="puzzles"),
] + static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)
如果需要其他信息,请告诉我。
filter.py
文件放在有效的Django应用程序中?你创建filter.py
的应用程序是否列在INSTALLED_APPS
中?文件夹是否被准确地命名为templatetags
?该文件夹内是否有一个__init__.py
文件?你是否在这行代码{{ user.profile.points|keyvalue:subject }}
之前调用了{% load filter %}
? - Vitor Freitas