现在我已经下载了所有的消息,并将它们存储到
Message[] temp;
如何获取每个消息的附件列表
List<File> attachments;
注意: 请不要使用第三方库,只使用JavaMail。
现在我已经下载了所有的消息,并将它们存储到
Message[] temp;
如何获取每个消息的附件列表
List<File> attachments;
注意: 请不要使用第三方库,只使用JavaMail。
没有异常处理,但是这里有:
List<File> attachments = new ArrayList<File>();
for (Message message : temp) {
Multipart multipart = (Multipart) message.getContent();
for (int i = 0; i < multipart.getCount(); i++) {
BodyPart bodyPart = multipart.getBodyPart(i);
if(!Part.ATTACHMENT.equalsIgnoreCase(bodyPart.getDisposition()) &&
StringUtils.isBlank(bodyPart.getFileName())) {
continue; // dealing with attachments only
}
InputStream is = bodyPart.getInputStream();
// -- EDIT -- SECURITY ISSUE --
// do not do this in production code -- a malicious email can easily contain this filename: "../etc/passwd", or any other path: They can overwrite _ANY_ file on the system that this code has write access to!
// File f = new File("/tmp/" + bodyPart.getFileName());
FileOutputStream fos = new FileOutputStream(f);
byte[] buf = new byte[4096];
int bytesRead;
while((bytesRead = is.read(buf))!=-1) {
fos.write(buf, 0, bytesRead);
}
fos.close();
attachments.add(f);
}
}
这个问题很久了,但也许它会对某些人有帮助。我想扩展David Rabinowitz的回答。
if(!Part.ATTACHMENT.equalsIgnoreCase(bodyPart.getDisposition()))
不能如您所期望地返回所有附件,因为您可能会有没有定义处理方式的混合部分邮件。
----boundary_328630_1e15ac03-e817-4763-af99-d4b23cfdb600
Content-Type: application/octet-stream;
name="00000000009661222736_236225959_20130731-7.txt"
Content-Transfer-Encoding: base64
那么在这种情况下,你也可以检查文件名。像这样:
if (!Part.ATTACHMENT.equalsIgnoreCase(part.getDisposition()) && StringUtils.isBlank(part.getFileName())) {...}
编辑
这里有一个使用上述条件的完整工作代码。因为每个部分都可以封装另一个部分,并且附件应该被嵌套在其中,所以递归用于遍历所有部分。
public List<InputStream> getAttachments(Message message) throws Exception {
Object content = message.getContent();
if (content instanceof String)
return null;
if (content instanceof Multipart) {
Multipart multipart = (Multipart) content;
List<InputStream> result = new ArrayList<InputStream>();
for (int i = 0; i < multipart.getCount(); i++) {
result.addAll(getAttachments(multipart.getBodyPart(i)));
}
return result;
}
return null;
}
private List<InputStream> getAttachments(BodyPart part) throws Exception {
List<InputStream> result = new ArrayList<InputStream>();
Object content = part.getContent();
if (content instanceof InputStream || content instanceof String) {
if (Part.ATTACHMENT.equalsIgnoreCase(part.getDisposition()) || StringUtils.isNotBlank(part.getFileName())) {
result.add(part.getInputStream());
return result;
} else {
return new ArrayList<InputStream>();
}
}
if (content instanceof Multipart) {
Multipart multipart = (Multipart) content;
for (int i = 0; i < multipart.getCount(); i++) {
BodyPart bodyPart = multipart.getBodyPart(i);
result.addAll(getAttachments(bodyPart));
}
}
return result;
}
以下是针对保存附件文件代码的一些时间节省技巧:
如果使用的是javax邮件版本1.4或更高版本,您可以使用以下代码:
// SECURITY LEAK - do not do this! Do not trust the 'getFileName' input. Imagine it is: "../etc/passwd", for example.
// bodyPart.saveFile("/tmp/" + bodyPart.getFileName());
替代
InputStream is = bodyPart.getInputStream();
File f = new File("/tmp/" + bodyPart.getFileName());
FileOutputStream fos = new FileOutputStream(f);
byte[] buf = new byte[4096];
int bytesRead;
while((bytesRead = is.read(buf))!=-1) {
fos.write(buf, 0, bytesRead);
}
fos.close();
bodyPart
需要先转换为 MimeBodyPart
,像这样:((MimeBodyPart) bodyPart).saveFile("/tmp/" + bodyPart.getFileName());
- yairMimeMessageParser parser = ....
parser.parse();
for(DataSource dataSource : parser.getAttachmentList()) {
if (StringUtils.isNotBlank(dataSource.getName())) {}
//use apache commons IOUtils to save attachments
IOUtils.copy(dataSource.getInputStream(), ..dataSource.getName()...)
} else {
//handle how you would want attachments without file names
//ex. mails within emails have no file name
}
}
返回带有附件的身体部位列表。
@Throws(Exception::class)
fun getAttachments(message: Message): List<BodyPart>{
val content = message.content
if (content is String) return ArrayList<BodyPart>()
if (content is Multipart) {
val result: MutableList<BodyPart> = ArrayList<BodyPart>()
for (i in 0 until content.count) {
result.addAll(getAttachments(content.getBodyPart(i)))
}
return result
}
return ArrayList<BodyPart>()
}
@Throws(Exception::class)
private fun getAttachments(part: BodyPart): List<BodyPart> {
val result: MutableList<BodyPart> = ArrayList<BodyPart>()
if (Part.ATTACHMENT == part.disposition && !part.fileName.isNullOrBlank()){
result.add(part)
}
val content = part.content
if (content is Multipart) {
for (i in 0 until (content ).count) {
val bodyPart = content.getBodyPart(i)
result.addAll(getAttachments(bodyPart)!!)
}
}
return result
}