我正在尝试通过外键来过滤结果集:
createCriteria(Person.class).add(Restrictions.ne("position", 1L)).list()
但是出现了这个异常:org.hibernate.PropertyAccessException: could not get a field value by reflection getter of com.example.model.Position.id
以下是必要的JPA实体(已经精简到必要字段):
@Entity
@Table
public class Person {
@Id
@GeneratedValue
private Long id;
@ManyToOne
@JoinColumn(nullable = false)
@ForeignKey(name = "person_position_fkey")
private Position position;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public Position getPosition() {
return position;
}
public void setPosition(Position position) {
this.position = position;
}
}
@Entity
@Table
public class Position {
@Id
@GeneratedValue
private Long id;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
}
Restrictions.ne("position.id", 1L)
。该语句的意思是筛选出"position.id"不等于1L的结果。 - Yurii Shylov