给定以下字符串:
let str = "#include \\u003Cunordered_map\\u003E\\u000D\\u000A"
如何在OCaml中将unicode-escape字符串解码为Unicode字符串或在我的情况下是Ascii字符串?
在Python中,我可以很容易地执行以下操作:
str.decode("unicode-escape")
给定以下字符串:
let str = "#include \\u003Cunordered_map\\u003E\\u000D\\u000A"
如何在OCaml中将unicode-escape字符串解码为Unicode字符串或在我的情况下是Ascii字符串?
在Python中,我可以很容易地执行以下操作:
str.decode("unicode-escape")
let decode s =
let re = Str.regexp "\\\\u[0-9a-fA-F][0-9a-fA-F][0-9a-fA-F][0-9a-fA-F]" in
let s1 n = String.make 1 (Char.chr n) in
let subst = function
| Str.Delim u -> s1 (int_of_string ("0x" ^ String.sub u 2 4))
| Str.Text t -> t
in
String.concat "" (List.map subst (Str.full_split re s))
val decode : string -> string = <fun>
# decode "#include \\u003Cunordered_map\\u003E\\u000D\\u000A";;
- : string = "#include <unordered_map>\r\n"
实际上,Python内置了解码这些序列的支持。
更新
为了支持所有四位十六进制转义序列"\uXXXX"
,通过转换为UTF-8,您可以使用以下代码:
let utf8encode s =
let prefs = [| 0x0; 0xc0; 0xe0 |] in
let s1 n = String.make 1 (Char.chr n) in
let rec ienc k sofar resid =
let bct = if k = 0 then 7 else 6 - k in
if resid < 1 lsl bct then
(s1 (prefs.(k) + resid)) ^ sofar
else
ienc (k + 1) (s1 (0x80 + resid mod 64) ^ sofar) (resid / 64)
in
ienc 0 "" (int_of_string ("0x" ^ s))
let decode2 s =
let re = Str.regexp "\\\\u[0-9a-fA-F][0-9a-fA-F][0-9a-fA-F][0-9a-fA-F]" in
let subst = function
| Str.Delim u -> utf8encode (String.sub u 2 4)
| Str.Text t -> t
in
String.concat "" (List.map subst (Str.full_split re s))
val utf8encode : string -> string = <fun>
val decode2 : string -> string = <fun>
# decode2 "#include \\u003Cunordered_map\\u003E\\u000D\\u000A";;
- : string = "#include <unordered_map>\r\n"
# print_endline (decode2 "\\u00A2");;
¢
- : unit = ()
# print_endline (decode2 "\\u20AC");;
€
- : unit = ()