我想要找到以下内容:
给定一个日期(datetime
对象),对应的星期几是什么?
例如,星期天是第一天,星期一是第二天……以此类推。
如果输入是今天的日期,该怎么办。
示例
>>> today = datetime.datetime(2017, 10, 20)
>>> today.get_weekday() # what I look for
输出可能为6
(因为今天是星期五)
datetime库有时在使用strptime()函数时会出现错误,因此我转而使用dateutil库。以下是如何使用它的示例:
from dateutil import parser
parser.parse('January 11, 2010').strftime("%a")
你会得到的输出是'Mon'
。如果你想要输出为 'Monday',可以使用以下代码:
parser.parse('January 11, 2010').strftime("%A")
这对我来说相当快速。我在使用datetime库时遇到了问题,因为我想存储星期几的名称而不是星期几的数字,并且使用datetime库的格式导致了问题。如果您没有遇到这个问题,那太棒了!但如果您有这个问题,您肯定可以选择这个方法,因为它具有更简单的语法。希望这能帮到您。
这段代码不需要星期几的注释。
我推荐使用这段代码~!
import datetime
DAY_OF_WEEK = {
"MONDAY": 0,
"TUESDAY": 1,
"WEDNESDAY": 2,
"THURSDAY": 3,
"FRIDAY": 4,
"SATURDAY": 5,
"SUNDAY": 6
}
def string_to_date(dt, format='%Y%m%d'):
return datetime.datetime.strptime(dt, format)
def date_to_string(date, format='%Y%m%d'):
return datetime.datetime.strftime(date, format)
def day_of_week(dt):
return string_to_date(dt).weekday()
dt = '20210101'
if day_of_week(dt) == DAY_OF_WEEK['SUNDAY']:
None
import datetime
DayL = ['Mon','Tues','Wednes','Thurs','Fri','Satur','Sun']
date = DayL[datetime.date(year,month,day).weekday()] + 'day'
#Set day, month, year to your value
#Now, date is set as an actual day, not a number from 0 to 6.
print(date)
def dow(year,month,day):
""" day of week, Sunday = 1, Saturday = 7
http://en.wikipedia.org/wiki/Zeller%27s_congruence """
m, q = month, day
if m == 1:
m = 13
year -= 1
elif m == 2:
m = 14
year -= 1
K = year % 100
J = year // 100
f = (q + int(13*(m + 1)/5.0) + K + int(K/4.0))
fg = f + int(J/4.0) - 2 * J
fj = f + 5 - J
if year > 1582:
h = fg % 7
else:
h = fj % 7
if h == 0:
h = 7
return h
fg
和 fj
的语句移动到条件内部,以防止不必要的计算。 - Tom Russell如果您不仅仅依赖于datetime
模块,那么calendar
可能是更好的选择。例如,以下代码将为您提供日期代码:
calendar.weekday(2017,12,22);
这个将会给你当天的日期:
days = ["Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"]
days[calendar.weekday(2017,12,22)]
["Monday","Tuesday","Wednesday","Thursday","Friday","Saturday","Sunday"][calendar.weekday(2017,12,22)]
import datetime
int(datetime.datetime.today().strftime('%w'))+1
+1
?在 Python 中,星期编号从周日开始为 0,周一为 1,这是常识。 - Nebulosar以下是将小端字符串日期列表转换为datetime
的方法:
import datetime, time
ls = ['31/1/2007', '14/2/2017']
for d in ls:
dt = datetime.datetime.strptime(d, "%d/%m/%Y")
print(dt)
print(dt.strftime("%A"))
这是一种全新的方式。星期天用数字0表示。
from datetime import datetime
today = datetime(year=2022, month=6, day=17)
print(today.toordinal()%7) # 5
yesterday = datetime(year=1, month=1, day=1)
print(today.toordinal()%7) # 1
datetime.date.today().toordinal()%7 + 1
所有的它们:
import datetime
today = datetime.date.today()
sunday = today - datetime.timedelta(today.weekday()+1)
for i in range(7):
tmp_date = sunday + datetime.timedelta(i)
print tmp_date.toordinal()%7 + 1, '==', tmp_date.strftime('%A')
输出:
1 == Sunday
2 == Monday
3 == Tuesday
4 == Wednesday
5 == Thursday
6 == Friday
7 == Saturday
import datetime
import calendar
day, month, year = map(int, input().split())
my_date = datetime.date(year, month, day)
print(calendar.day_name[my_date.weekday()])
08 05 2015
Friday
strftime(“%A”)
而不是weekday()
来获取星期几的名称。 - Lekr0