代码:
Function ShowDataPatient($idURL)
{
$query =" select * from cmu_list_insurance,cmu_home,cmu_patient where cmu_home.home_id = (select home_id from cmu_patient where patient_hn like '%$idURL%')
AND cmu_patient.patient_hn like '%$idURL%'
AND cmu_list_insurance.patient_id like (select patient_id from cmu_patient where patient_hn like '%$idURL%') ";
$result = pg_query($query) or die('Query failed: ' . pg_last_error());
while ($row = pg_fetch_array($result))
{
$hn = $row["patient_hn"];
$pid = $row["patient_id"];
$datereg = $row["patient_date_register"];
$prefix = $row["patient_prefix"];
$fname = $row["patient_fname"];
$lname = $row["patient_lname"];
$age = $row["patient_age"];
$sex = $row["patient_sex"];
}
return array($hn, $pid, $datereg, $prefix, $fname, $lname, $age, $sex);
}
错误:
Notice: Undefined variable: hn in C:\xampp\htdocs\...
Notice: Undefined variable: pid in C:\xampp\htdocs\...
Notice: Undefined variable: datereg in C:\xampp\htdocs\...
Notice: Undefined variable: prefix in C:\xampp\htdocs\...
Notice: Undefined variable: fname in C:\xampp\htdocs\...
Notice: Undefined variable: lname in C:\xampp\htdocs\...
Notice: Undefined variable: age in C:\xampp\htdocs\...
Notice: Undefined variable: sex in C:\xampp\htdocs\...
我该如何修复这个问题?
while()
块,因此在尝试返回它们时没有设置任何变量。 - fedorqui$row
将不存在,随后您的本地变量副本也将未定义。因此,请检查查询语句。 - marioreturn pg_fetch_array($result)
并且摆脱所有变量。 - Dr. McKay