我正在尝试将一个字符串转换为长整型。听起来很简单,但我仍然得到相同的错误。我尝试过:
include <iostream>
include <string>
using namespace std;
int main()
{
string myString = "";
cin >> myString;
long myLong = atol(myString);
}
但总是出现错误:
.../main.cpp:12: error: cannot convert 'std::string {aka std::basic_string<char>}' to 'const char*' for argument '1' to 'long int atol(const char*)'
发生了。参考资料中如下所述:
long int atol ( const char * str );
有需要帮忙的吗?