Swift（iOS 8 SDK）：将Unmanaged <ABMultiValueRef>转换为ABMultiValueRef

Question

我需要将来自AddressBook框架的此函数返回值进行转换：

ABRecordCopyValue(nil, kABPersonPhoneProperty)

转换为类型为ABMultiValueRef的值。

当前将此函数标记为：

func ABRecordCopyValue(record: ABRecordRef!, property: ABPropertyID) -> Unmanaged<AnyObject>!

那么我可以这样将它转换为Unmanaged：

ABRecordCopyValue(person, kABPersonPhoneProperty) as Unmanaged<ABMultiValueRef>

那么我该如何将它转换为ABMultiValueRef，以便可以将其传递给这个函数？

func ABMultiValueGetIndexForIdentifier(multiValue: ABMultiValueRef!, identifier: ABMultiValueIdentifier) -> CFIndex

我做了这个：

let managedPhones = Unmanaged.fromOpaque(phones.toOpaque()).takeUnretainedValue() as ABMultiValueRef

我不断遇到这个编译器错误：

Bitcast requires both operands to be pointer or neither
%89 = bitcast %objc_object* %88 to %PSs9AnyObject_, !dbg !325
LLVM ERROR: Broken function found, compilation aborted!
Command /Applications/Xcode6-Beta3.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/swift failed with exit code 1

- Vandad Nahavandipoor

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我遇到了相同的错误。我卡在获取已排序书籍记录这一步了 :( - Anton

我听说这是因为在iOS 8 SDK Beta 4中，苹果尚未启用AddressBook框架上的CF_IMPLICIT_BRIDGING_ENABLED。 - Vandad Nahavandipoor

好的，现在我明白了 :( - Anton

我现在已经发布了我的解决方案。你不能说成ABMultiValueRef，你应该说“as NSObject as ABMultiValueRef”。希望这可以帮到你。 - Vandad Nahavandipoor

Answer 1

我找到了解决方案：

func peoplePickerNavigationController(
  peoplePicker: ABPeoplePickerNavigationController!,
  didSelectPerson person: ABRecordRef!) {

    /* Do we know which picker this is? */
    if peoplePicker != personPicker{
      return
    }

    /* Get all the phone numbers this user has */
    let unmanagedPhones = ABRecordCopyValue(person, kABPersonPhoneProperty)
    let phones: ABMultiValueRef =
    Unmanaged.fromOpaque(unmanagedPhones.toOpaque()).takeUnretainedValue()
      as NSObject as ABMultiValueRef

    let countOfPhones = ABMultiValueGetCount(phones)

    for index in 0..<countOfPhones{
      let unmanagedPhone = ABMultiValueCopyValueAtIndex(phones, index)
      let phone: String = Unmanaged.fromOpaque(
        unmanagedPhone.toOpaque()).takeUnretainedValue() as NSObject as String

      println(phone)
    }  
}

- Vandad Nahavandipoor

---

与其使用 fromOpaque/toOpaque 的方式，为什么不直接使用 let phones: ABMultiValueRef = unmanagedPhones.takeUnretainedValue() 和 let phone = unmanagedPhone.takeUnretainedValue() as String 呢？ - Rob

这是一个Beta 5修复版本。苹果已经解决了这个问题，所以不需要再进行所有的非托管业务了。 - Vandad Nahavandipoor

Answer 2

如果有人正在寻找一种在Swift 2中处理ABRecords的最终方法，这里就是：

func peoplePickerNavigationController(peoplePicker: ABPeoplePickerNavigationController, didSelectPerson person: ABRecord) {

    let firstName = ABRecordCopyValue(person, kABPersonFirstNameProperty).takeRetainedValue()
    let lastName = ABRecordCopyValue(person, kABPersonLastNameProperty).takeRetainedValue()

    var emails:[String] = []
    let emailRecords = ABRecordCopyValue(person, kABPersonEmailProperty).takeRetainedValue() as ABMultiValueRef
    let emailsCount = ABMultiValueGetCount(emailRecords)
    for index in 0 ..< emailsCount {
        if let email = ABMultiValueCopyValueAtIndex(emailRecords, index).takeRetainedValue() as? String {
            emails.append(email)
        }
    }

    print("Contact selected. firstName: \(firstName), lastName: \(lastName), emails: \(emails)")

}

- zh.

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真是个救命稻草！ - Roi Mulia

Answer 3

我也有同样的问题，这可能是编译器的问题。如果你也想关注我的帖子ABPeoplePickerNavigationController shouldContinueAfterSelectingPerson deprecated Swift。

- marchiore