Hibernate JPA中的OneToOne

Question

Hibernate JPA中的OneToOne

4

我正在尝试关联两张表

用户和地址一个用户有一个地址，一个地址只属于一个用户。键由地址的ID列出。所以我先创建我的地址，然后创建一个用户并将其与地址ID关联起来。但我无法成功操作，返回以下错误：

Error creating bean with name 'entityManagerFactory' defined in class path resource [org / springframework / boot / autoconfigure / orm / jpa / HibernateJpaConfiguration.class]: Invocation of init method failed; nested exception is java.lang.NullPointerException: Cannot invoke "org.hibernate.mapping.PersistentClass.getTable ()" because "classMapping" is null

我完全是对Hibernate一窍不通，但是我需要完成这个项目以便于我大学的课程，敬请谅解我的无知。

以下是我的代码：

用户/用户 Class:

import org.hibernate.validator.constraints.br.CPF;

import javax.persistence.*;
import javax.validation.constraints.*;


public class Usuario{

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Integer id;

    @Column
    @NotNull
    @Size(min = 5,max = 30)
    @Pattern(regexp = "^[a-zA-Z\s]*$", message = "Nome inválido! Digite apenas letras e espaçamento") //Permite apenas letras e espaço
    private String nome;

    @NotNull
    @CPF
    private String cpf;

    @NotNull
    @Email
    private String email;

    @NotNull
    @Size(min = 5,max = 12)
    private String senha;

    private Integer telefone;

    @DecimalMin("0")
    @DecimalMax("5")
    private Double avaliacao;

    @NotNull
    @OneToOne(cascade = CascadeType.ALL,mappedBy = "id")
    private Endereco endereco;

    //Atributos para usuários autônomos

    private Boolean isAutonomo;

    private String categoriaAutonomo;

    private Double precoAutonomo;

//Getters and Setters

地址/终端类

import javax.persistence.*;
import javax.validation.constraints.NotNull;
import javax.validation.constraints.Size;

@Entity
@Table(name = "endereco")
public class Endereco {

    @Id
    @OneToOne
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Integer id;

    @NotNull
    @Size(min = 8,max = 8)
    private String cep;

    @NotNull
    private String bairro;

    @NotNull
    private String logradouro;

    @NotNull
    private Integer numeroLogradouro;

    private String complemento;

    @NotNull
    @Size(min = 2,max = 2)
    private String uf;

    @NotNull
    private String cidade;

控制器

import br.com.bandtec.projetocaputeam.dominio.*;
import br.com.bandtec.projetocaputeam.repository.*;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.http.ResponseEntity;
import org.springframework.web.bind.annotation.*;

import javax.validation.Valid;
import java.util.List;

@RestController
@RequestMapping("/caputeam")
public class CaputeamController {

    @Autowired
    private UsuariosRepository usuariosRepository;

    @Autowired
    private EnderecoRepository enderecoRepository;

//--- USERS
    @GetMapping("/usuarios")
    public ResponseEntity getUsuarios(){
        List<Usuario> usuarios = usuariosRepository.findAll();
        return !usuarios.isEmpty() ? ResponseEntity.status(200).body(usuarios) :
                                     ResponseEntity.status(204).build();
    }

    @PostMapping("/cadastrar-usuario")
    public ResponseEntity cadastrarUsuario(@RequestBody @Valid Usuario novoUsuario){
        usuariosRepository.save(novoUsuario);
        return ResponseEntity.ok().build();
    }

//--- ADRESS
    @PostMapping("/cadastrar-endereco")
    public ResponseEntity cadastrarEndereco(@RequestBody @Valid Endereco novoEndereco){
        enderecoRepository.save(novoEndereco);
        return ResponseEntity.ok().build();
    }
}

应用程序

import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;

@SpringBootApplication
public class ProjetoCaputeamApplication {

    public static void main(String[] args) {
        SpringApplication.run(ProjetoCaputeamApplication.class, args);
    }

}

这是我的逻辑模型：

编辑：我试图删除“mapped by”部分，并从Address中删除@OneToOne，但现在当我尝试发送Adress的POST时，它返回以下错误：

org.h2.jdbc.JdbcSQLIntegrityConstraintViolationException: Referential integrity constraint violation: "FKMXNOON0IKGA83W1A203Y6OFPN: PUBLIC.ENDERECO FOREIGN KEY(ID) REFERENCES PUBLIC.USUARIO(ID) (1)"; SQL statement:
insert into endereco (bairro, cep, cidade, complemento, logradouro, numero_logradouro, uf, id) values (?, ?, ?, ?, ?, ?, ?, ?) [23506-200]

就像他没有填写任何地址字段一样。

我是这样用Postman发送我的POST请求的：

{
    "bairro": "Vila Prmavera",
    "cep": "03388110",
    "cidade": "São Paulo",
    "complemento": "b1",
    "logradouro": "Rua das dores",
    "numeroLogradouro": 7,
    "uf": "SP"
}

- BaaDe

1个回答

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- Panagiotis Bougioukos · Accepted Answer

不要使用ID进行映射。映射指的是实体映射而不是ID映射。

public class Endereco {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    private Integer id;

    @OneToOne
    private Usuario usuario

     ....
   }

如果您不希望Endereco保留对Usuario的引用，只需将其删除即可。但是您不能在id字段上放置@OneToOne。如果您只有一侧使用@OneToOne，则还需要使用注释@MapsId。

public class Usario {

        @NotNull
        @MapsId
        @OneToOne(cascade = CascadeType.ALL)
        private Endereco endereco;

 public class Endereco {
    
        @Id
        @GeneratedValue(strategy = GenerationType.AUTO)
        private Integer id

       }

@OneToOne因为试图将关联映射到一个实体（即数据库中的表）。对于id来说，在数据库中没有任何实体或表，所以会报错。