我已经将弹出菜单添加到我的Android应用程序中。我已经为弹出菜单创建了一个XML文件,并且代码也运行良好。现在我无法弄清楚如何处理弹出菜单项的点击。我尝试使用PopupMenu.OnMenuItemClickListener,但没有成功。我该怎么做?
我的弹出菜单代码:
ImageButton button = (ImageButton) view.findViewById(R.id.popUp_song);
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
PopupMenu popup = new PopupMenu(activity, v);
Menu m = popup.getMenu();
MenuInflater inflater = popup.getMenuInflater();
inflater.inflate(R.menu.song_popup, popup.getMenu());
if (audio.getDownload().equals("0")) {
m.removeItem(R.id.add_download);
}
popup.show();
}
});
XML
<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android"
style="@style/ToolBarStyle">
<item
android:id="@+id/add_queue"
android:title="Add to queue" />
<item
android:id="@+id/play_next"
android:title="Add to favourite" />
<item
android:id="@+id/add_download"
android:title="Download" />
</menu>