我有一段代码连接到本地的Graphite(实际上只是运行在本地主机上的
启动后,我看到了这个输出:
nc -l -p 2023
):getCarbonAddr :: Config -> IO SockAddr
getCarbonAddr cfg = do
let host = (graphiteHost . graphiteConfig) cfg
let port = (graphitePort . graphiteConfig) cfg
-- addrInfos <- getAddrInfo (Just defaultHints)
addrInfos <- getAddrInfo Nothing
(Just host)
(Just (show port))
putStrLn $ "addrInfos: " ++ show addrInfos
c <- case addrInfos of
(addrInfo : _) -> return (addrAddress addrInfo)
_ -> unsupportedAddressError host
return c
where
unsupportedAddressError h = ioError $ userError $
"unsupported address: " ++ h
主机和端口的配置值分别为"localhost"和2023。当我在我的OS X上升级到Yosemite后运行此程序时,我看到以下崩溃:
addrInfos: [AddrInfo {addrFlags = [], addrFamily = AF_INET6, addrSocketType = Datagram, addrProtocol = 17, addrAddress = [::1]:2023, addrCanonName = Nothing},AddrInfo {addrFlags = [], addrFamily = AF_INET6, addrSocketType = Stream, addrProtocol = 6, addrAddress = [::1]:2023, addrCanonName = Nothing},AddrInfo {addrFlags = [], addrFamily = AF_INET, addrSocketType = Datagram, addrProtocol = 17, addrAddress = 127.0.0.1:2023, addrCanonName = Nothing},AddrInfo {addrFlags = [], addrFamily = AF_INET, addrSocketType = Stream, addrProtocol = 6, addrAddress = 127.0.0.1:2023, addrCanonName = Nothing},AddrInfo {addrFlags = [], addrFamily = AF_INET6, addrSocketType = Datagram, addrProtocol = 17, addrAddress = [fe80::1%lo0]:2023, addrCanonName = Nothing},AddrInfo {addrFlags = [], addrFamily = AF_INET6, addrSocketType = Stream, addrProtocol = 6, addrAddress = [fe80::1%lo0]:2023, addrCanonName = Nothing}]
LocalJob: connect: unsupported operation (Address family not supported by protocol family)
这个问题对我来说很奇怪,所以我决定运行这个C程序(在Google中搜索“getaddrinfo”示例,更改主机名和端口,并添加ai_family的打印):
#include <stdio.h>
#include <stdlib.h>
#include <netdb.h>
#include <netinet/in.h>
#include <sys/socket.h>
#ifndef NI_MAXHOST
#define NI_MAXHOST 1025
#endif
int main(void)
{
struct addrinfo *result;
struct addrinfo *res;
int error;
/* resolve the domain name into a list of addresses */
error = getaddrinfo("localhost", "2023", NULL, &result);
if (error != 0)
{
fprintf(stderr, "error in getaddrinfo: %s\n", gai_strerror(error));
return EXIT_FAILURE;
}
/* loop over all returned results and do inverse lookup */
for (res = result; res != NULL; res = res->ai_next)
{
char hostname[NI_MAXHOST] = "";
error = getnameinfo(res->ai_addr, res->ai_addrlen, hostname, NI_MAXHOST, NULL, 0, 0);
if (error != 0)
{
fprintf(stderr, "error in getnameinfo: %s\n", gai_strerror(error));
continue;
}
if (*hostname != '\0')
printf("hostname: %s. ai_family: %i\n", hostname, res->ai_family);
}
freeaddrinfo(result);
return EXIT_SUCCESS;
}
启动后,我看到了这个输出:
➜ getaddrinfotest ./main
hostname: localhost. ai_family: 30
hostname: localhost. ai_family: 30
hostname: localhost. ai_family: 2
hostname: localhost. ai_family: 2
hostname: localhost. ai_family: 30
hostname: localhost. ai_family: 30
所以,ai_family 30 看起来很奇怪。根据 socket.h sources 中的理解,它是 AF_TIPC 协议,这是我之前从未听说过的相当罕见的东西。我还打开了 haskell 的 packFamily' sources,惊讶地发现它在那里没有处理值为 30(不知道 AF_TIPC)。
我的问题是:现在该怎么办?我是否正确理解了问题?haskell 是否应该更好地处理未知的 ai family?//谢谢!
更新:通过提示使用 ipv4,我解决了一个问题:
addrInfos <- getAddrInfo (Just (defaultHints { addrFamily=AF_INET }))
(Just host)
(Just (show port))
但我仍然想知道如何以“正确的方式”解决这个问题。
AF_*
名称而不是数字的原因是数字在每个系统上都不同。Linux 的socket.h
在非 Linux 操作系统上无法告诉你 30 的含义。最好检查一下自己机器上的socket.h
。(我预测 30 将是AF_INET6
) - user2404501AddrInfo {addrFlags = [],addrFamily = AF_INET6,addrSocketType = Datagram,addrProtocol = 17,addrAddress = [::1]:2023,addrCanonName = Nothing}
我看到它正确地将 addrFamily 解析为 AF_INET6,但我想知道 addrProtocol 17 是什么意思。我找到的唯一有价值的 17 是#define AF_ROUTE 17 /* Internal Routing Protocol */
。 - Konstantine RybnikovIPPROTO_UDP
。如果您想使用getaddrinfo
结果中的该字段,它应该放在socket()
的第三个参数中。通常你可以把它设置为 0,因为地址族和套接字类型 (SOCK_DGRAM
、SOCK_STREAM
等) 足以唯一确定一个协议。 - user2404501