如何使用Laravel 5.1执行原始查询？

Question

如何使用Laravel 5.1执行原始查询？

114

我需要在我的数据库上运行一个小查询，在MySQL Workbench中它能够正常工作。基本上，这是一个带有LEFT JOIN的SELECT语句和一个带有LEFT JOIN的UNION语句。

SELECT
    cards.id_card,
    cards.hash_card,
    cards.`table`,
    users.name,
    0 as total,
    cards.card_status,
    cards.created_at
FROM cards
LEFT JOIN users
ON users.id_user = cards.id_user
WHERE hash_card NOT IN ( SELECT orders.hash_card FROM orders )
UNION
SELECT
    cards.id_card,
    orders.hash_card,
    cards.`table`,
    users.name,
    sum(orders.quantity*orders.product_price) as total, 
    cards.card_status, 
    max(orders.created_at) 
FROM menu.orders
LEFT JOIN cards
ON cards.hash_card = orders.hash_card
LEFT JOIN users
ON users.id_user = cards.id_user
GROUP BY hash_card
ORDER BY id_card ASC

我试图将它翻译成Laravel，但没有成功。

$cards = Card::selectRaw('cards.id_card, cards.hash_card ,cards.table, users.name, 0 as total, cards.card_status, cards.created_at as last_update')
                ->leftJoin('users','users.id_user','=','cards.id_user')
                ->whereNotIn( 'hash_card', Order::select('orders.hash_card')->get() )
                ->union(
                        Order::selectRaw('cards.id_card, orders.hash_card, cards.table, users.name, sum(orders.quantity*orders.product_price) as total, cards.card_status, max(orders.created_at) as last_update')
                        ->leftJoin('cards','cards.hash_card','=','orders.hash_card')
                        ->leftJoin('users','users.id_user','=','cards.id_user')
                )
                ->groupBy('hash_card')
                ->orderBy('cards.id_card','asc')
                ->get();

我遇到了以下错误信息：

ErrorException in Builder.php line 1249: Undefined property: Illuminate\Database\Eloquent\Builder::$bindings

在Laravel中，我应该如何执行完全原始的查询或以正确的方式编写查询语句？

- Sandro Wiggers

5个回答

54

    DB::statement("your query")

我在迁移中使用它为列添加索引

- ДароваДарова

3

Laravel文档中的示例：

$users = DB::table('users')
    ->selectRaw('count(*) as user_count, status')
    ->where('status', '<>', 1)
    ->groupBy('status')
    ->get();

另一个例子：

$products = DB::table('products')
    ->leftjoin('category','category.product_id','=','products.id')
    ->selectRaw('COUNT(*) as nbr', 'products.*')
    ->groupBy('products.id')
    ->get();

另一个例子 - 我们甚至可以在同一条语句中执行avg()和count()。

$salaries = DB::table('salaries')
    ->selectRaw('companies.name as company_name, avg(salary) as avg_salary, count(*) as people_count')
    ->join('companies', 'salaries.company_id', '=', 'companies.id')
    ->groupBy('companies.id')
    ->orderByDesc('avg_salary')
    ->get();

Credits: https://blog.quickadminpanel.com/5-ways-to-use-raw-database-queries-in-laravel/

- Gediminas Šukys

0

另外，你可以使用

DB::unprepared()

- Martin Tonev

-30

你也可以像这样运行原始查询。

DB::table('setting_colleges')->first();

- pankaj

5

这不是 Laravel 中的原始查询方法，它只是获取该表的第一行。 - Root

这是错误的查询。:( - Nilesh Bavliya

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- Sandro Wiggers · Accepted Answer

我在这个主题中找到了解决方案，然后我写下了以下代码:

$cards = DB::select("SELECT
        cards.id_card,
        cards.hash_card,
        cards.`table`,
        users.name,
        0 as total,
        cards.card_status,
        cards.created_at as last_update
    FROM cards
    LEFT JOIN users
    ON users.id_user = cards.id_user
    WHERE hash_card NOT IN ( SELECT orders.hash_card FROM orders )
    UNION
    SELECT
        cards.id_card,
        orders.hash_card,
        cards.`table`,
        users.name,
        sum(orders.quantity*orders.product_price) as total, 
        cards.card_status, 
        max(orders.created_at) last_update 
    FROM menu.orders
    LEFT JOIN cards
    ON cards.hash_card = orders.hash_card
    LEFT JOIN users
    ON users.id_user = cards.id_user
    GROUP BY hash_card
    ORDER BY id_card ASC");