将一个以字符串编码的数组转换成对象

Question

将一个以字符串编码的数组转换成对象

3

我从服务器获取的是一个字符串形式的数组，其中包含所有对象的坐标，如下所示：

"[[[-0.340254,51.605946],[-0.340278,51.605685],[-0.339718,51.604400],
 [-0.339280,51.603746],[-0.338915,51.603454],[-0.338657,51.603018],
 [-0.338427,51.601810],[-0.338518,51.600885],[-0.337471,51.599908],
 [-0.337378,51.599682],[-0.337456,51.599116],[-0.336860,51.597669],
 [-0.335843,51.597043],[-0.335635,51.596816],[-0.335112,51.595720],
 [-0.335232,51.594400],[-0.335057,51.593273],[-0.334827,51.592847],
 [-0.333187,51.591889],[-0.333236,51.590945],[-0.332894,51.590446],
 [-0.332727,51.589868],[-0.332791,51.589320],[-0.332638,51.589156],
 [-0.332028,51.587295],[-0.332326,51.585438],[-0.332243,51.585365],
 [-0.332292,51.585186],[-0.331651,51.582991],[-0.333713,51.581096],
 [-0.334020,51.580570],[-0.334055,51.580013],[-0.337963,51.580123],
 [-0.340047,51.579954],[-0.341778,51.579979],[-0.341883,51.579881]]]"

如何将此转换为数组？提前感谢您！

所以我想要它的形式为[[Double]]。

let objects = [[[-0.340254,51.605946],[-0.340278,51.605685],[-0.339718,51.604400],
 [-0.339280,51.603746],[-0.338915,51.603454],[-0.338657,51.603018],
 [-0.338427,51.601810],[-0.338518,51.600885],[-0.337471,51.599908],
 [-0.337378,51.599682],[-0.337456,51.599116],[-0.336860,51.597669],
 [-0.335843,51.597043],[-0.335635,51.596816],[-0.335112,51.595720],
 [-0.335232,51.594400],[-0.335057,51.593273],[-0.334827,51.592847],
 [-0.333187,51.591889],[-0.333236,51.590945],[-0.332894,51.590446],
 [-0.332727,51.589868],[-0.332791,51.589320],[-0.332638,51.589156],
 [-0.332028,51.587295],[-0.332326,51.585438],[-0.332243,51.585365],
 [-0.332292,51.585186],[-0.331651,51.582991],[-0.333713,51.581096],
 [-0.334020,51.580570],[-0.334055,51.580013],[-0.337963,51.580123],
 [-0.340047,51.579954],[-0.341778,51.579979],[-0.341883,51.579881]]]

所以如果我执行objects[0][0]，它应该返回[-0.340254,51.605946]。

func convert(s: String) -> [[[Double]]]{

do{

    let array = try NSJSONSerialization.JSONObjectWithData(s.dataUsingEncoding(NSUTF8StringEncoding)!, options: []) as? [[[Double]]]
    return array!

}catch{

}
return [[[]]]

}

- Minhal Khan

这是一个数组。请给我们展示一个你想要它看起来像什么的例子。 - quelquecosa

1

这是一个字符串，用引号括起来。 - Minhal Khan

请不要在问题中包含答案。如果有答案解决了您的问题，请将答案标记为已接受；如果您自己解决了问题，也可以发布自己的答案。谢谢。 - Eric Aya

1个回答

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可以查看英文原文，
原文链接

- Mazyod · Accepted Answer

你只是有一个 JSON 响应的三维数组。我将你的字符串加载到 Swift REPL 中，然后可以这样解析：

import Foundation

let s = /* your string */
let array = NSJSONSerialization.JSONObjectWithData(s.dataUsingEncoding(NSUTF8StringEncoding)!, options: []) as? [[[Double]]]

输出

$R3: [[[Double]]]? = 1 value {
  [0] = 36 values {
...

代码示例

func convert(s: String) -> [[[Double]]] {

    if let data = s.dataUsingEncoding(NSUTF8StringEncoding),
        let object = try? NSJSONSerialization.JSONObjectWithData(data, options: []),
        let array = object as? [[[Double]]]
    {
        return array
    }

    return [[[]]]
}