移除Laravel中过滤集合时的键值

Question

在使用 Laravel 5.2 中的 filter 函数时，我遇到了一个问题。在过滤后，我得到了一些意外的键，比如“0”、“1”、“2”等等，我该如何去除它们？

过滤之前：

[
  {
    "id": 1,
    "user_id": 11,
    "location": "1",
    "content": "1",
    "interest_id": 1,
    "longitude": 1,
    "latitude": 1,
    "place_id": "1",
    "created_at": "2016-06-09 15:44:18",
    "updated_at": "2016-06-02 14:28:42",
    "deleted_at": null
  },
  {
    "id": 2,
    "user_id": 12,
    "location": "Forest Lake QLD, Australia",
    "content": "I'm newbie. Hello everybody",
    "interest_id": 1,
    "longitude": 152.9692508,
    "latitude": -27.6236519,
    "place_id": "ChIJB_NHl8hOkWsRMIne81qjAgU",
    "created_at": "2016-06-09 14:28:42",
    "updated_at": "2016-06-09 14:28:42",
    "deleted_at": null
  },
  {
    "id": 8,
    "user_id": 11,
    "location": "Hendra QLD, Australia",
    "content": "What time is it?",
    "interest_id": 1,
    "longitude": 153.0635202,
    "latitude": -27.4225981,
    "place_id": "ChIJAXNg5PBYkWsRIIve81qjAgU",
    "created_at": "2016-06-09 14:28:42",
    "updated_at": "2016-06-09 14:28:42",
    "deleted_at": null
  },
  {
    "id": 9,
    "user_id": 11,
    "location": "Hendra QLD, Australia",
    "content": "Nice Cream!!!!????????",
    "interest_id": 2,
    "longitude": 153.0635202,
    "latitude": -27.4225981,
    "place_id": "ChIJAXNg5PBYkWsRIIve81qjAgU",
    "created_at": "2016-06-09 14:28:42",
    "updated_at": "2016-06-09 14:28:42",
    "deleted_at": null
  },
  {
    "id": 4,
    "user_id": 17,
    "location": "Forest Lake QLD, Úc",
    "content": "Have a nice day!",
    "interest_id": 1,
    "longitude": 152.9692508,
    "latitude": -27.6236519,
    "place_id": "ChIJB_NHl8hOkWsRMIne81qjAgU",
    "created_at": "2016-06-09 14:28:42",
    "updated_at": "2016-06-09 14:28:42",
    "deleted_at": null
  },
  {
    "id": 7,
    "user_id": 18,
    "location": "Hendra QLD, Australia",
    "content": "Where is Kiet Bui? ❤️❤️❤️❤️❤️",
    "interest_id": 1,
    "longitude": 153.0635202,
    "latitude": -27.4225981,
    "place_id": "ChIJAXNg5PBYkWsRIIve81qjAgU",
    "created_at": "2016-06-09 14:28:42",
    "updated_at": "2016-06-09 14:28:42",
    "deleted_at": null
  }
]

过滤后，例如id > 5：

{
  "2": {
    "id": 8,
    "user_id": 11,
    "location": "Hendra QLD, Australia",
    "content": "What time is it?",
    "interest_id": 1,
    "longitude": 153.0635202,
    "latitude": -27.4225981,
    "place_id": "ChIJAXNg5PBYkWsRIIve81qjAgU",
    "created_at": "2016-06-09 14:28:42",
    "updated_at": "2016-06-09 14:28:42",
    "deleted_at": null
  },
  "3": {
    "id": 9,
    "user_id": 11,
    "location": "Hendra QLD, Australia",
    "content": "Nice Cream!!!!????????",
    "interest_id": 2,
    "longitude": 153.0635202,
    "latitude": -27.4225981,
    "place_id": "ChIJAXNg5PBYkWsRIIve81qjAgU",
    "created_at": "2016-06-09 14:28:42",
    "updated_at": "2016-06-09 14:28:42",
    "deleted_at": null
  },
  "5": {
    "id": 7,
    "user_id": 18,
    "location": "Hendra QLD, Australia",
    "content": "Where is Kiet Bui? ❤️❤️❤️❤️❤️",
    "interest_id": 1,
    "longitude": 153.0635202,
    "latitude": -27.4225981,
    "place_id": "ChIJAXNg5PBYkWsRIIve81qjAgU",
    "created_at": "2016-06-09 14:28:42",
    "updated_at": "2016-06-09 14:28:42",
    "deleted_at": null
  }
}

如何从结果中移除键2、3和5，并仅获得像过滤之前的数组一样的数组。感谢任何帮助。
编辑：我的代码：

 $result = $result->filter(function ($item) {
                return $item->id > 5;
            })->all();

- maphongba008

---

请给我你的代码，你尝试了什么？ - rome 웃

为什么不尝试使用 ->reject(function ($row) {return $row->id<5;}); 呢？ - Safoor Safdar

@SafoorSafdar: 我已经尝试过了，但它返回相同的结果 :( - maphongba008

Answer 1

试着添加values()

$result = $result->filter(function ($item) {
                return $item->id > 5;
            })->values()->all();

- mace

---

谢谢。对我也有帮助。 - Gabriel Augusto

我得到了略微不同的东西。我只是使用了$collection->values()，而不是$collection->values()->all()。all()返回一个数组，但是values()返回一个无键集合。 - Tarek Adam

我使用flatten()函数，它也会删除键。 - Fred Lai

我认为不需要在文档中使用 all()，详细信息请阅读此处 https://laravel.com/docs/8.x/collections#method-values - Jazuly

Answer 2

我在排序时遇到了同样的问题： 例如，按积分和进球数对比赛结果进行排序。排序在结果中添加键属性。因此，我在最后使用->values() ->all()获取一个没有键的数组值。

例如： $sorted = $resultados->sortByDesc('pts')->sortByDesc('gf')->values()->all();

在你的情况下： $filteredValues = $filtered->values()->all();

希望这能帮到你。

- Manuel Eduardo Romero

Answer 3

如果你想使用filter()助手，那么你不能这样做，因为这就是这个助手的工作方式。我的意思是这个方法没有任何参数之类的东西。你只能重建返回的集合。

或者，你可以使用filter()方法代码来创建自己的助手，比如myFilter()并稍微修改一下，例如：

public function myFilter(callable $callback)
{
    $return = [];

    foreach ($this->items as $key => $value) {
        if ($callback($value, $key)) {
            // $return[$key] = $value; // original line from filter() method
            $return[] = $value; // Here you want to remove $key
        }
    }

    return new static($return);
}

或者你可以直接使用带有索引的集合。我是说通常你使用集合来迭代它，这些索引不会干扰你。

- Alexey Mezenin

Answer 4

$result = $result->filter(function ($item) {
                return $item->id < 5;
            })->all();

享受!!

        $collection = collect([1, 2, 3, 4]);

        $filtered = $collection->filter(function ($item) {
            return $item < 2;
        });

        $filtered->all();
        return $filtered;

结果：

[ 1 ]

但是：

    $collection = collect([1, 2, 3, 4]);

    $filtered = $collection->filter(function ($item) {
        return $item > 2;
    });

    $filtered->all();
    return $filtered;

结果：{ "2": 3, "3": 4 }

不知道如何，为什么...

- rome 웃