我收到一个错误：调用初始化方法失败；嵌套异常是org.hibernate.MappingException：实体映射中的重复列。

Question

我会尽力为您翻译中文，以下是需要翻译的内容：

我遇到了错误：

初始化方法调用失败；嵌套异常为 org.hibernate.MappingException：在实体映射中重复的列：com.messagemanager.domain.User 列：id（应该使用 insert="false" update="false" 进行映射）

这是我的实体类：

@MappedSuperclass
public abstract class BaseEntity{

    @Id
    @Column(nullable = false, unique = true, name = "id", insertable = false, updatable = false)
    @GeneratedValue(strategy= GenerationType.AUTO)
    private Long id;

    public Long getId() {
        return id;
    }   

    public void setId(Long id) {
        this.id = id;
    }
}


@Entity
@Table(name = "User")
public class User  extends BaseEntity implements Serializable{
    @Column(name = UserFieldsKey.ID, length = 50, nullable = false)
    private String name;

    @Column(updatable = false, insertable = false)
    @Transient
    private List<Message> listMessage = new ArrayList<>();

    public static class UserFieldsKey{
        public static final String NAME = "name";
    }

    public User() {
    }

    @OneToMany(fetch = FetchType.EAGER, mappedBy = "user")
    public List<Message> getListMessage() {
        return listMessage;
    }

    public void setListMessage(List<Message> listMessage) {
        this.listMessage = listMessage;
    }


    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }
}


@Entity
@Table(name = "Message")
public class Message extends BaseEntity implements Serializable{
    @Column(name = MessageFieldsKey.MESSAGE, length = 500, nullable = false)
    private String message;

    @ManyToOne(cascade=CascadeType.ALL, fetch = FetchType.EAGER)
    @JoinColumn(name="user")
    private User user;

    @Column(name = "id_user")
    private Long id_user;

    public Long getId_user() {
        return id_user;
    }

    public void setId_user(Long id_user) {
        this.id_user = id_user;
    }

    public static class MessageFieldsKey{
        public static final String MESSAGE = "mes";
    }

    public String getMessage() {
        return message;
    }

    public User getUser() {
        return user;
    }

    public Message() {
    }

    public Message(String message, User user) {
        this.message = message;
        this.user = user;
    }

    public void setMessage(String message) {
        this.message = message;
    }

    public void setUser(User user) {
        this.user = user;
    }
}

有什么想法吗？

附注：非常感谢！

- Dmitriy S

---

UserFieldsKey.ID 的值是多少？ - Bhargav Patel

@DmitriyS，这个问题是我尝试回答的那一个吗？ - Eugene

该帖子已关闭。谢谢大家！ - Dmitriy S

Answer 1

问题已解决）我在表之间的关系上弄错了。

- Dmitriy S

Answer 2

看起来是因为你有这个：

@ManyToOne(cascade=CascadeType.ALL, fetch = FetchType.EAGER)
@JoinColumn(name="user")
private User user;

这将映射到User.id; 而在Message中，您已经有一个id，因为您正在扩展BaseEntity

- Eugene