SQL计算日期差(DateDiff)不包括周末和公共假期

6

我希望能够找到一个解决方案,计算两个日期之间不包括周末和公共假日的天数。

目前我有以下代码:

SELECT evnt.event_id,
       evnt.date_from,
       evnt.date_to,
       DATEDIFF(DD, evnt.date_from, evnt.date_to) 
       - (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2) 
       - CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END 
       + CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
       --- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to
       FROM events AS evnt

在我取消注释这部分代码之前,一切都正常:

- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to

我想要实现的目标是获取日期范围内的工作日数量。问题出在最后一步,我试图从这个范围中减去所有公共假日天数。
有人能帮忙解决这个最后一步吗?似乎我做错了什么,但我无法弄清楚。
提前感谢您。

可能是[如何在MySQL中计算日期差异(不包括周末和假期)]的重复问题(https://dev59.com/vGkv5IYBdhLWcg3wzkDa)。 - Abhijit Annaldas
6个回答

7

试一下这个:

SELECT evnt.event_id,
   evnt.date_from,
   evnt.date_to,
   DATEDIFF(DD, evnt.date_from, evnt.date_to) 
   - (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2) 
   - CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END 
   + CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
   - (SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
   FROM events AS evnt

取消注释应该是一个子查询

--- COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to

像这样:

- (SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)

很好的解决方案,但如果同一天有多个公共假日,你将会休息。 - Luke

1
Kajiyama,试试这个:
SELECT evnt.event_id,
       evnt.date_from,
       evnt.date_to,
       DATEDIFF(DD, evnt.date_from, evnt.date_to) 
       - (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2) 
       - CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END 
       + CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
       -(SELECT COUNT(*) FROM public_holidays AS h WHERE h.date_from BETWEEN evnt.date_from AND evnt.date_to)
       FROM events AS evnt

看起来在COUNT(*)之前缺少了SELECT语句。


1

这里是与使用公共表达式(CTE)不同的答案

;with  t as
(
select COUNT(*) as cnt FROM public_holidays 
WHERE date_from BETWEEN evnt.date_from AND evnt.date_to
)
SELECT evnt.event_id,
       evnt.date_from,
       evnt.date_to,
       DATEDIFF(DD, evnt.date_from, evnt.date_to) 
       - (DATEDIFF(WK, evnt.date_from, evnt.date_to) * 2) 
       - CASE WHEN DATEPART(DW, evnt.date_from) = 1 THEN 1 ELSE 0 END 
       + CASE WHEN DATEPART(DW, evnt.date_to) = 1 THEN 1 ELSE 0 END AS Date_Diff
       - (select cnt from T)
       FROM events AS evnt

1

(我看到这个问题已经有答案了,但我还是想提出我的建议...)

也许将每天作为一行创建一个日历表,而不是单独创建一个公共假期表,可能不是一个坏主意。请查看文章SQL Server Calendar Table以获取演示和可下载的T-SQL代码。该文章包括几篇后续文章,用于查询和财政年度。


0

我在其他地方看到了一些类似下面的例子elsewhere

如果您正在寻找“工作日差异”,那么请将其与普通日历日差异(即DATEDIFF)进行比较。两个相邻工作日之间的差异在两种情况下都应为1天。其他解决方案会导致例如星期二和星期三之间有两个工作日的情况。

DECLARE @StartDate DATETIME
DECLARE @EndDate DATETIME
SET @StartDate = '1/17/19'
SET @EndDate = '1/18/19'

-- CalendarDateDiff vs Business Date Diff
SELECT
    DATEDIFF(d, @StartDate, @EndDate) AS CalendarDateDiff
    , (DATEDIFF(dd, @StartDate, @EndDate) + 1) 
    -1
    -(DATEDIFF(wk, @StartDate, @EndDate) * 2)
    -(CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
    -(CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END) AS CalendarDays

0

三个标量函数:ShiftHolidayToWorkday、GetHoliday和GetWorkDays

create FUNCTION [dbo].[ShiftHolidayToWorkday](@date date)
RETURNS date
AS
BEGIN
    IF DATENAME( dw, @Date ) = 'Saturday'
        SET @Date = DATEADD(day, - 1, @Date)

    ELSE IF DATENAME( dw, @Date ) = 'Sunday'
        SET @Date = DATEADD(day, 1, @Date)

    RETURN @date
END
GO

create FUNCTION [dbo].[GetHoliday](@date date)
RETURNS varchar(50)
AS
BEGIN
    declare @s varchar(50)

    SELECT @s = CASE
        WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]  ) + '-01-01') = @date THEN 'New Year'
        WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]+1) + '-01-01') = @date THEN 'New Year'
        WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]  ) + '-07-04') = @date THEN 'Independence Day'
        WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]  ) + '-12-25') = @date THEN 'Christmas Day'
        --WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-12-31') = @date THEN 'New Years Eve'
        --WHEN dbo.ShiftHolidayToWorkday(CONVERT(varchar, [Year]) + '-11-11') = @date THEN 'Veteran''s Day'

        WHEN [Month] = 1  AND [DayOfMonth] BETWEEN 15 AND 21 AND [DayName] = 'Monday' THEN 'Martin Luther King Day'
        WHEN [Month] = 5  AND [DayOfMonth] >= 25             AND [DayName] = 'Monday' THEN 'Memorial Day'
        WHEN [Month] = 9  AND [DayOfMonth] <= 7              AND [DayName] = 'Monday' THEN 'Labor Day'
        WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 22 AND 28 AND [DayName] = 'Thursday' THEN 'Thanksgiving Day'
        WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 23 AND 29 AND [DayName] = 'Friday' THEN 'Day After Thanksgiving'
        ELSE NULL END
    FROM (
        SELECT
            [Year] = YEAR(@date),
            [Month] = MONTH(@date),
            [DayOfMonth] = DAY(@date),
            [DayName]   = DATENAME(weekday,@date)
    ) c

    RETURN @s
END
GO

create FUNCTION [dbo].GetHolidays(@year int)
RETURNS TABLE 
AS
RETURN (  
    select dt, dbo.GetHoliday(dt) as Holiday
    from (
        select dateadd(day, number, convert(varchar,@year) + '-01-01') dt
        from master..spt_values 
        where type='p' 
        ) d
    where year(dt) = @year and dbo.GetHoliday(dt) is not null
)

create proc UpdateHolidaysTable
as

if not exists(select TABLE_NAME from INFORMATION_SCHEMA.TABLES where TABLE_NAME = 'Holidays')
    create table Holidays(dt date primary key clustered, Holiday varchar(50))

declare @year int
set @year = 1990

while @year < year(GetDate()) + 20
begin
    insert into Holidays(dt, Holiday)
    select a.dt, a.Holiday
    from dbo.GetHolidays(@year) a
        left join Holidays b on b.dt = a.dt
    where b.dt is null

    set @year = @year + 1
end

create FUNCTION [dbo].[GetWorkDays](@StartDate DATE = NULL, @EndDate DATE = NULL)
RETURNS INT 
AS
BEGIN
    IF @StartDate IS NULL OR @EndDate IS NULL
        RETURN  0

    IF @StartDate >= @EndDate 
        RETURN  0

    DECLARE @Days int
    SET @Days = 0

    IF year(@StartDate) * 100 + datepart(week, @StartDate) = year(@EndDate) * 100 + datepart(week, @EndDate) 
        --same week
        select @Days = (DATEDIFF(dd, @StartDate, @EndDate))
      - (CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
      - (CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
      - (select count(*) from Holidays where dt between @StartDate and @EndDate)
    ELSE
        --diff weeks
        select @Days = (DATEDIFF(dd, @StartDate, @EndDate) + 1)
      - (DATEDIFF(wk, @StartDate, @EndDate) * 2)
      - (CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
      - (CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)
      - (select count(*) from Holidays where dt between @StartDate and @EndDate)
 
    RETURN  @Days
END

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