我相对比较新学C++。最近的作业要求我将许多char缓冲区(来自结构体/套接字等)转换为字符串。我一直在使用以下变化,但它们似乎很笨拙。有没有更好的方法来做这种事情?
#include <iostream>
#include <string>
using std::string;
using std::cout;
using std::endl;
char* bufferToCString(char *buff, int buffSize, char *str)
{
memset(str, '\0', buffSize + 1);
return(strncpy(str, buff, buffSize));
}
string& bufferToString(char* buffer, int bufflen, string& str)
{
char temp[bufflen];
memset(temp, '\0', bufflen + 1);
strncpy(temp, buffer, bufflen);
return(str.assign(temp));
}
int main(int argc, char *argv[])
{
char buff[4] = {'a', 'b', 'c', 'd'};
char str[5];
string str2;
cout << bufferToCString(buff, sizeof(buff), str) << endl;
cout << bufferToString(buff, sizeof(buff), str2) << endl;
}