如何使用Swift从一个视图控制器导航到另一个视图控制器

Question

我想从一个视图控制器导航到另一个视图控制器。如何将以下 Objective-C 代码转换为 Swift？

UIViewController *viewController = [[self storyboard] instantiateViewControllerWithIdentifier:@"Identifier"];
UINavigationController *navi = [[UINavigationController alloc] initWithRootViewController:viewController];
[self.navigationController pushViewController:navi animated:YES];

- sathish

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请查看：https://dev59.com/nV4c5IYBdhLWcg3w7t_E#38244058 - Jayprakash Dubey

Answer 1

创建一个Swift文件 (SecondViewController.swift) 用于第二个视图控制器，在适当的函数中输入以下内容：

let secondViewController = self.storyboard.instantiateViewControllerWithIdentifier("SecondViewController") as SecondViewController
self.navigationController.pushViewController(secondViewController, animated: true)

---

Swift 2+

let mapViewControllerObj = self.storyboard?.instantiateViewControllerWithIdentifier("MapViewControllerIdentifier") as? MapViewController
self.navigationController?.pushViewController(mapViewControllerObj!, animated: true)

Swift 4

let vc = UIStoryboard.init(name: "Main", bundle: Bundle.main).instantiateViewController(withIdentifier: "IKDetailVC") as? IKDetailVC
self.navigationController?.pushViewController(vc!, animated: true)

- Audrey Sobgou Zebaze

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@audrey，你好，如何设置navigationController？ - Sanjivani

@Sanjivani，你的视图控制器可以使用Storyboard创建，并将你的firstViewController分配为rootViewController。你的导航控制器(Swift)类将如下所示： import UIKit`class SwiftNavigationController: UINavigationController { init(nibName nibNameOrNil: String?, bundle nibBundleOrNil: NSBundle?) { super.init(nibName: nibNameOrNil, bundle: nibBundleOrNil) // 自定义初始化 }override func viewDidLoad() { super.viewDidLoad() }}` - Audrey Sobgou Zebaze

我也遇到了同样的问题，我卡在了如何从一个 ViewController 跳转到另一个 ViewController 上。当我尝试运行你的代码时，在第二行代码处出现了错误：unexpectedly found nil while unwrapping an Optional value。请帮忙解决一下。 - Raghavendra

我在使用animated参数时遇到了问题，错误信息如下： "无法将表达式的类型'$T7??'转换为类型'BooleanLiteralConvertible'"。 - Morkrom

你需要确保你的控制器嵌入到 NavigationController 中才能使其正常工作，否则会出现错误。 - kakubei

Answer 2

根据我的经验，navigationController 值为 nil，所以我将我的代码改为：

let next = self.storyboard?.instantiateViewControllerWithIdentifier("DashboardController") as! DashboardController
self.presentViewController(next, animated: true, completion: nil)

别忘了在StoryBoard的identity inspector中设置视图控制器的StoryBoard Id

- Mojtaba Yeganeh

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这是因为您的视图控制器没有嵌入导航视图控制器。 - Francis Reynolds

Answer 3

如果您不希望出现返回按钮（这也是我的情况，因为我想在用户登录后展示），则可以通过以下方法设置导航控制器的根目录：

let vc = self.storyboard?.instantiateViewControllerWithIdentifier("YourViewController") as! YourViewController
        let navigationController = UINavigationController(rootViewController: vc)
        self.presentViewController(navigationController, animated: true, completion: nil)

- Keith Holliday

Answer 4

SWIFT 3.01

let secondViewController = self.storyboard?.instantiateViewController(withIdentifier: "Conversation_VC") as! Conversation_VC
self.navigationController?.pushViewController(secondViewController, animated: true)

- Yaroslav Dukal

Answer 5

在 Swift 4.0 中

var viewController: UIViewController? = storyboard().instantiateViewController(withIdentifier: "Identifier")
var navi = UINavigationController(rootViewController: viewController!)
navigationController?.pushViewController(navi, animated: true)

- Protocol

Answer 6

let storyBoard: UIStoryboard = UIStoryboard(name: "Main", bundle: nil)
let home = storyBoard.instantiateViewController(withIdentifier: "HOMEVC") as! HOMEVC
navigationController?.pushViewController(home, animated: true);

- Shanu Singh

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我认为这不是Swift或Objc语法。 - SPatel

Answer 7

在Swift 4.1和Xcode 10中，这里的AddFileViewController是第二个视图控制器。故事板ID为AFVC。

let next = self.storyboard?.instantiateViewController(withIdentifier: "AFVC") as! AddFileViewController
self.present(next, animated: true, completion: nil)

//OR

//If your VC is DashboardViewController
let dashboard = self.storyboard?.instantiateViewController(withIdentifier: "DBVC") as! DashboardViewController
self.navigationController?.pushViewController(dashboard, animated: true)

如果需要，使用线程(thread)。

例如：

DispatchQueue.main.async { 
    let next = self.storyboard?.instantiateViewController(withIdentifier: "AFVC") as! AddFileViewController
    self.present(next, animated: true, completion: nil) 
}

如果你想在一段时间后移动。

例如：

//To call or execute function after some time(After 5 sec)
DispatchQueue.main.asyncAfter(deadline: .now() + 5.0) {
    let next = self.storyboard?.instantiateViewController(withIdentifier: "AFVC") as! AddFileViewController
    self.present(next, animated: true, completion: nil) 
} 

- Naresh

Answer 8

在Swift 3中，

let nextVC = self.storyboard?.instantiateViewController(withIdentifier: "NextViewController") as! NextViewController        
self.navigationController?.pushViewController(nextVC, animated: true)

- Zeeshan

Answer 9

Swift 3

let secondviewController:UIViewController =  self.storyboard?.instantiateViewController(withIdentifier: "StoryboardIdOfsecondviewController") as? SecondViewController

self.navigationController?.pushViewController(secondviewController, animated: true)

- SAURAV

Answer 10

Swift 5.0 最佳实践

更加可重用和易读

创建一个协议

protocol Storyboarded { }

现在创建协议的扩展。

extension Storyboarded where Self: UIViewController {
    
    static func instantiateFromMain() -> Self {
        let storyboardIdentifier = String(describing: self)
        // `Main` can be your stroyboard name.
        let storyboard = UIStoryboard(name: "Main", bundle: Bundle.main)
        
        guard let vc = storyboard.instantiateViewController(withIdentifier: storyboardIdentifier) as? Self else {
            fatalError("No storyboard with this identifier ")
        }
        return vc
    }
}
// Make a ViewController extension to use on all of your ViewControllers
extension UIViewController: Storyboarded {}

如何使用

  let vc = MyViewController.instantiateFromMain()
  //here you can pass any data to the next view controller. for example we have a variable with name `myString` in our next view contoller and we want to pass the data my `self viewController`
  vc.myString = "This string passed by MyViewController"
  self.navigationController?.pushViewController(vc, animated: true)

注意：你需要在Storyboard上使用与UIViewController类相同的标识符。请查看下面的示例。

- Rashid Latif

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如果它是Storyboarded的扩展，如何调用它 - Pramod Shukla

@Pramod Shukla 确认你的 ViewController 上使用了 Storyboarded 协议，然后你就可以使用它了。或者创建一个视图控制器扩展，类似于这样 extension UIViewController: Storyboarded {}。 - Rashid Latif

@pramod-shukla 我也更新了我的答案，你可以相应地使用它。 - Rashid Latif