Flot图表无法显示

Question

Flot图表无法显示

3

我正在尝试使用Flot库生成图形。

var d= [ [1293840000000,332],[1293926400000,321],[1294012800000,310],[1294099200000,299],[1294185600000,288],[1294272000000,277],[1294358400000,266],[1294444800000,255],[1294531200000,244],[1294617600000,233],[1294704000000,222],[1294790400000,211],[1294876800000,200],[1294963200000,189],[1295049600000,178],[1295136000000,167],[1295222400000,156],[1295308800000,145],[1295395200000,134],[1295481600000,123],[1295568000000,112],[1295654400000,101],[1295740800000,90],[1295827200000,79],[1295913600000,68],[1296000000000,57],[1296086400000,46],[1296172800000,35],[1296259200000,24],[1296345600000,13]];

$.plot($("#placeholder"), [d], { xaxis: { mode: "time" } });

上述代码生成了图表。但是当我将包含在变量 d[] 中的数据尝试使用时...

var d=[formateddata3];

当 formatteddata3 包含

[1293840000000,332],[1293926400000,321],[1294012800000,310],[1294099200000,299],
[1294185600000,288],[1294272000000,277],[1294358400000,266],[1294444800000,255],
[1294531200000,244],[1294617600000,233],[1294704000000,222],[1294790400000,211],
[1294876800000,200],[1294963200000,189],[1295049600000,178],[1295136000000,167],
[1295222400000,156],[1295308800000,145],[1295395200000,134],[1295481600000,123],
[1295568000000,112],[1295654400000,101],[1295740800000,90],[1295827200000,79],
[1295913600000,68],[1296000000000,57],[1296086400000,46],[1296172800000,35],
[1296259200000,24],[1296345600000,13]

我在考虑的问题是将变量的值传递到数组中。我正在使用for循环构建formateddata3。希望有人能帮我找到正确的方法。

另外，当我用没有传递变量的值来警示d时，我得到了：

1293840000000,332,1293926400000,321,1294012800000,310,1294099200000,299,
1294185600000,288

如果我使用传递的变量时进行警报，则会得到以下结果：

[1293840000000,332],[1293926400000,310],[1294012800000,288]

第一个函数生成图表...

//以下是完整的代码

var d1=[{!formateddata1}];
var d2=[{!formateddata2}];
var start = new Date(document.getElementById('Stardate').value);
var end= new Date(document.getElementById('CompleteDate').value);
var noofdays=datediff(start ,end,'days') ;
var hours= document.getElementById('page1:form2:amount').value ; 
var totalhours= {!est_project_hours};
var formateddata3='';
var cumhours=0;

for (var i=0;i<noofdays;i++)
{

 if (i==0)
 {
 cumhours=totalhours;

 formateddata3='['+start.getTime()+ ','+cumhours+'],[';
 alert(formateddata3);
 }
 else if(i==noofdays-1)
 {
 start.setDate(start.getDate()+1);
cumhours=cumhours-hours;

 formateddata3=formateddata3+start.getTime()+ ','+cumhours+']';


  }
  else
  {
  start.setDate(start.getDate()+1);
  cumhours=cumhours-hours;

  formateddata3=formateddata3+start.getTime()+ ','+cumhours+'],['
  }

  }   
   // when i use the d3 with these values the graph works  
  //var d3=[ [1293840000000,332],[1293926400000,321],[1294012800000,310],     [1294099200000,299],[1294185600000,288],[1294272000000,277],[1294358400000,266],[1294444800000,255],[1294531200000,244],[1294617600000,233],[1294704000000,222],[1294790400000,211],[1294876800000,200],[1294963200000,189],[1295049600000,178],[1295136000000,167],[1295222400000,156],[1295308800000,145],[1295395200000,134],[1295481600000,123],[1295568000000,112],[1295654400000,101],[1295740800000,90],[1295827200000,79],[1295913600000,68],[1296000000000,57],[1296086400000,46],[1296172800000,35],[1296259200000,24],[1296345600000,13]];
  //alert([formateddata3]);
  var d3=[];
  var d3=[formateddata3];// but when i use it like this it doesnt work
  alert('d3 value is '+d3);
  alert('d1 value is '+d1);
  alert('d2 value is '+d2);
  j$.plot(j$("#placeholder"),[ { label: "Timelog", data:d1 },{ label: "Avg", data:d2   },{ label: "Simulated", data:d3}],
 {
 series: {
 lines: { show: true },
 points: { show: true }
 },


 xaxis:
  { mode: "time",
  min: {!startdate},
   max: {!enddate}
  }
  ,yaxis: {
  min:0, tickSize: 5
  }

  });

- Prady

1个回答

网页内容由stack overflow 提供, 点击上面的

可以查看英文原文，
原文链接

- Reiner Gerecke · Accepted Answer

更新

看起来你正在将你的formateddata3构建为一个字符串。flot期望一个JavaScript数组。

var formateddata3 = new Array();

for (var i=0;i<noofdays;i++)
{
   if (i==0)
   {
      cumhours=totalhours;
   }
   else if(i==noofdays-1)
   {
      start.setDate(start.getDate()+1);
      cumhours=cumhours-hours;
   }
   else
   {
      start.setDate(start.getDate()+1);
      cumhours=cumhours-hours;
   }
   formateddata3.push(new Array(start.getTime(), cumhours));
}

直接将格式化数据3传递给flot即可。