我正在从安卓应用程序中向HTTPS服务器进行webservice调用。下面是代码片段，借助它我能够成功进行webservice调用并获取响应。
我的问题是，在向HTTPS服务器进行调用之前，我们需要执行任何附加步骤来加密数据吗？ 因为从安卓分析器中，我可以看到所有的Web请求都以明文格式呈现。据我所知，请求在进行HTTPS调用之前会被加密。
public static WebServiceResp makeWebServiceCall(String XML, String urlPath) throws IOException{
//Code to make a web service HTTP request
String responseString = "";
String outputString = "";
String wsURL = urlPath;
URL url = new URL(wsURL);
URLConnection connection = url.openConnection();
HttpsURLConnection httpConn = (HttpsURLConnection)connection;
ByteArrayOutputStream bout = new ByteArrayOutputStream();
//System.out.println(XML);
byte[] buffer = new byte[XML.length()];
buffer = XML.getBytes();
bout.write(buffer);
byte[] b = bout.toByteArray();
// Set the appropriate HTTP parameters.
httpConn.setRequestProperty("Content-Length",
String.valueOf(b.length));
httpConn.setRequestProperty("Content-Type", "text/xml; charset=utf-8");
httpConn.setRequestMethod("POST");
httpConn.setRequestProperty("Cache-Control", "no-cache");
httpConn.setDoOutput(true);
httpConn.setDoInput(true);
OutputStream out = httpConn.getOutputStream();
//Write the content of the request to the outputstream of the HTTP Connection.
out.write(b);
out.close();
//Ready with sending the request.
//Check the status
int status = httpConn.getResponseCode();
Log.d(TAG, "makeWebServiceCall: "+"Processing Status: "+status);
BufferedReader in;
if (status <= 200) {
//Read the response.
Log.d(TAG, "makeWebServiceCall: Getting Input Stream");
InputStreamReader isr =
new InputStreamReader(httpConn.getInputStream());
in = new BufferedReader(isr);
}else{
//Read the response.
Log.d(TAG, "makeWebServiceCall: Getting Error Stream");
InputStreamReader isr =
new InputStreamReader(httpConn.getErrorStream());
in = new BufferedReader(isr);
}
//Write the SOAP message response to a String.
while ((responseString = in.readLine()) != null) {
outputString = outputString + responseString;
}
Log.d(TAG, "makeWebServiceCall: WebServiceResponse " + outputString);
//Parse the String output to a org.w3c.dom.Document and be able to reach every node with the org.w3c.dom API.
Document document = Utils.parseXmlFile(outputString);
//NodeList nodeLst = document.getElementsByTagName("GetWeatherResult");
// String weatherResult = nodeLst.item(0).getTextContent();
//System.out.println("Weather: " + weatherResult);
//Write the SOAP message formatted to the console.
WebServiceResp webServiceResp = new WebServiceResp();
webServiceResp.setDocument(document);
webServiceResp.setStatus(status);
return webServiceResp;
}