有没有一种方法在Common Lisp中将整数解析为它们的字符等效物?
我已经寻找了整个上午,只找到了char-int...
我已经寻找了整个上午,只找到了char-int...
* (char-int #\A)
65
一些其他来源也声称存在 int-char
* (int-char 65)
; in: INT-CHAR 65
; (INT-CHAR 65)
;
; caught STYLE-WARNING:
; undefined function: INT-CHAR
;
; compilation unit finished
; Undefined function:
; INT-CHAR
; caught 1 STYLE-WARNING condition
debugger invoked on a UNDEFINED-FUNCTION:
The function COMMON-LISP-USER::INT-CHAR is undefined.
Type HELP for debugger help, or (SB-EXT:EXIT) to exit from SBCL.
restarts (invokable by number or by possibly-abbreviated name):
0: [ABORT] Exit debugger, returning to top level.
("undefined function")
然而,我真正需要的是将1
转换为#\1
的方法。
具体该如何实现呢?