如何在Selenium Python中使用索引号访问XPath？

Question

我只想访问一个XPath。但是在检查菜单中搜索时，它找到了5个结果。我想访问其中的一个而不是5个。如何使用索引编号实现？就像...

xpath = "//a[@role='button']" # 5 elements available with this xpath
modified_xpath = "//a[@role='button'][2]" # I'm trying with the index number.
driver.find_element_by_xpath(modified_xpath).click() # But It's not working.

“它不起作用了！”

- Priya

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find_elements_by_xpath returns a list, remove the index lookup in the xpath and index into the returned list? driver.find_elements_by_xpath(modified_xpath)[2] - Iain Shelvington

什么是错误？分享页面的HTML或URL。 - cruisepandey

显示以下错误selenium.common.exceptions.InvalidSelectorException: Message: invalid selector: Unable to locate an element with the xpath expression //a[@role='button'] because of the following error: SyntaxError: Failed to execute 'evaluate' on 'Document': The string '//a[@role='button']' is not a valid XPath expression. - Priya

Answer 1

您可以按照以下代码进行操作--

    xpath = "//a[@role='button']" 
    xpaths = driver.find_elements_by_xpath(xpath)
    xpaths[2].click()

希望它能够正常工作。

- Jawad