我有一个矩形,它围绕中心旋转,我还有另一个矩形,我想连接到旋转矩形的右上角。问题是我不知道如何获取该角落,以便第二个矩形始终粘在那个角上。
这是我的示例代码。现在第二个矩形将始终处于相同的位置,这并不是我要的结果。
package Test;
import java.awt.*;
import java.awt.event.*;
import java.awt.geom.*;
import javax.swing.*;
class Test{
public static void main(String[] args){
new Test();
}
public Test(){
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
JFrame frame = new JFrame("Test");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setLayout(new BorderLayout());
frame.add(new Graphic());
frame.setSize(1000,700);
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
}
class Graphic extends JPanel{
private int x, y, windowW, windowH;
private double angle;
private Rectangle rect1, rect2;
private Path2D path;
private Timer timer;
private AffineTransform rotation;
public Graphic(){
windowW = (int) Toolkit.getDefaultToolkit().getScreenSize().getWidth();
windowH = (int) Toolkit.getDefaultToolkit().getScreenSize().getHeight();
path = new Path2D.Double();
rotation = new AffineTransform();
angle = 0;
x = windowW / 2;
y = windowH / 2;
timer = new Timer(100, new ActionListener(){
@Override
public void actionPerformed(ActionEvent e){
angle += .1;
if(angle > 360) angle -= 360;
repaint();
}
});
timer.start();
}
@Override
public void paintComponent(Graphics g){
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g;
rotation.setToTranslation(500, 200);
rotation.rotate(angle, 32, 32);
rect1 = new Rectangle(0, 0, 64, 64);
path = new Path2D.Double(rect1, rotation);
rect2 = new Rectangle(path.getBounds().x, path.getBounds().y, 10, 50);
g2d.fill(path);
g2d.fill(rect2);
}
}
angle
设置的限制似乎表明你想用角度来表示它;然而,rotate
函数的第一个参数是弧度。条件if(angle > 360) angle -= 360
实际上会在达到时导致奇怪的跳跃,矩形旋转的速度比你想要的快得多。 - Arend