我最近开始学习如何使用Python解析XML文件。我参考了这篇教程:http://pyxml.sourceforge.net/topics/howto/node12.html。
当我运行下面的代码时,出现了错误:
当我运行下面的代码时,出现了错误:
Traceback (most recent call last):
File "C:\Users\Name\Desktop\pythonxml\tutorials\pythonxml\pyxml sourceforge\5.1 Comic Colection\SearchForComic.py", line 30, in -toplevel-
dh = FindIssue('sandman', '62')
TypeError: __init__() takes exactly 1 argument (3 given)
代码:
from xml.sax import saxutils
class FindIssue(saxutils.DefaultHandler):
def __init___(self, title, number):
self.search_title, self.search_number = title, number
def startElement(self, name, attrs):
#if it's not a comic element, ignore it
if name!= 'comic': return
# look for the title and number sttributes (see text)
title = attrs.get('title', None)
number = attrs.get('number', None)
if (title == self.search_title and
number == self.search_number):
print title, '#' +str (number), 'found'
from xml.sax import make_parser
from xml.sax.handler import feature_namespaces
if __name__ == '__main__':
#Create a parser
parser = make_parser()
#tell the parser that we are not interested in XML namespaces
parser.setFeature(feature_namespaces, 0)
#create the handler
dh = FindIssue('sandman', '62')
#tell the parse to use our handler
parser.setContentHandler(dh)
#parse the input
parser.parse('collection.xml')
最后一行代码中,我将文件传递给了当前工作目录中,这样写是正确的吗?
__init__
不存在,Python 就会退回到只接受self
参数的默认构造函数,因此 Python 抱怨函数参数过多,而你认为它们是正确的数量。 - Joe Day