以编程方式更改PopupMenu项的标题

Question

我有一个PopupMenu，里面有4个选项：添加好友、添加邻居、添加同事和添加粉丝。我想做的是，如果你点击了“添加好友”，那么该选项将变为“移除好友”。

到目前为止，这是我尝试过的：

活动：

private Menu menuOpts;

public void showPopup(View v) {
    Context wrapper = new ContextThemeWrapper(this, R.style.PopupPerfilAjeno);
    PopupMenu popup = new PopupMenu(wrapper, v);
    popup.setOnMenuItemClickListener(this);
    popup.inflate(R.menu.menu);
    popup.show();

    menuOpts = popup.getMenu();
}

@Override
public boolean onMenuItemClick(MenuItem item) {
    switch (item.getItemId()) {
        case R.id.add_friend:
            String add_as_friend = getString(R.string.add_as_friend );

            if (item.getTitle().toString().equals(add_as_friend )) {
                addContact(1, item);
            }
            else {
                removeContact(1, item);
            }
            return true;
        case R.id.add_workmate:
            //
            return true;
        case R.id.add_neighbour:
            //
            return true;
        case R.id.add_fan:
            //
            return true;
        default:
            return false;
    }
}
// circle: 1 = friend, 2 = workmate, 3 = neighbour, 4 = fan
private void addContact(final int circle, final MenuItem item) {

    switch (circle) {
        case 1:
            menuOpts.findItem(R.id.add_friend).setTitle(R.string.remove_friend);
             // this won't work either:
             // item.setTitle(R.string.remove_friend);
             break;
        case 2:
            menuOpts.findItem(R.id.add_workmate).setTitle(R.string.remove_workmate);
             break;
        case 3:
            menuOpts.findItem(R.id.add_neighbour).setTitle(R.string.remove_neighbour);
             break;
        case 4:
            menuOpts.findItem(R.id.add_fan).setTitle(R.string.remove_fan);
             break;
     }
 }

menu.xml:

<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:app="http://schemas.android.com/apk/res-auto"
    xmlns:android="http://schemas.android.com/apk/res/android">
    <item
        android:id="@+id/add_friend"
        android:orderInCategory="100"
        android:title="@string/add_as_friend"
        app:showAsAction="always" />
    <item
        android:id="@+id/add_workmate"
        android:orderInCategory="100"
        android:title="@string/add_as_workmate"
        app:showAsAction="always" />
    <item
        android:id="@+id/add_neighbour"
        android:orderInCategory="100"
        android:title="@string/add_as_neighbour"
        app:showAsAction="always" />
    <item
        android:id="@+id/add_fan"
        android:orderInCategory="100"
        android:title="@string/add_as_fan"
        app:showAsAction="always" />
</menu>

- guillefix

---

将所有项目添加到菜单中，并根据需要更改它们的可见性。我认为你无法更改文本。 - itzhar

https://dev59.com/U2w05IYBdhLWcg3wuUKY - Anjani Mittal

你点击的是哪个控件？是ListView或RecyclerView中的项，还是像TextView这样的简单视图？ - user8959091

Answer 1

我已找到解决方案。 我添加了4个布尔变量，并像这样修改了showPopup和addContact方法：

private boolean friend, workmate, neighbour, fan;

public void showPopup(View v) {
    Context wrapper = new ContextThemeWrapper(this, R.style.PopupPerfilAjeno);
    PopupMenu popup = new PopupMenu(wrapper, v);
    popup.setOnMenuItemClickListener(this);
    popup.inflate(R.menu.menu);

    Menu menuOpts = popup.getMenu();

    if (friend) {
        menuOpts.getItem(0).setTitle(R.string.remove_friends);
    }
    if (workmate) {
        menuOpts.getItem(1).setTitle(R.string.remove_workamtes);
    }
    if (neighbour) {
        menuOpts.getItem(2).setTitle(R.string.remove_neighbours);
    }
    if (fan) {
        menuOpts.getItem(3).setTitle(R.string.remove_fans);
    }

    popup.show();
}

private void addContact(final int circle) {

    switch (circle) {
        case 1:
             friend = true;
             workmate = false;
             neighbour = false;
             fan = false;
             break;
        case 2:
             friend = false;
             workmate = true;
             neighbour = false;
             fan = false;
             break;
        case 3:
             friend = false;
             workmate = false;
             neighbour = true;
             fan = false;
             break;
        case 4:
             friend = false;
             workmate = false;
             neighbour = false;
             fan = true;
             break;
     }
 }

- guillefix

Answer 2

再次显示弹出窗口时，膨胀另一个菜单。

  public void showPopup(View v) {
    Context wrapper = new ContextThemeWrapper(this, R.style.PopupPerfilAjeno);
    PopupMenu popup = new PopupMenu(wrapper, v);
    popup.setOnMenuItemClickListener(this);
    if (condition) popup.inflate(R.menu.menu);
    else popup.inflate(R.menu.menu2);
    popup.show();

    menuOpts = popup.getMenu();
}

- kttn

Answer 3

Kotlin解决方案：

var popup = PopupMenu(this,view)
popup.inflate(R.menu.my_popup)
popup.menu[0].title = "custom string"
popup.show()

- thefatb0b

---

请阅读[回答]并[编辑]您的回答，其中包含说明为什么此代码实际上可以解决手头的问题。请记住，您不仅要解决问题，还要教育原帖作者和任何未来的读者。 - Adriaan