如何从XmlNode实例获取xpath

解决您问题的另一种方法可能是通过自定义属性“标记”您稍后想要识别的xml节点：

var id = _currentNode.OwnerDocument.CreateAttribute("some_id");
id.Value = Guid.NewGuid().ToString();
_currentNode.Attributes.Append(id);

newOrOldDocument.SelectSingleNode(string.Format("//*[contains(@some_id,'{0}')]", id));

最近我也需要做这个。只需要考虑元素即可。以下是我的解决方案：

    private string GetPath(XmlElement el)
    {
        List<string> pathList = new List<string>();
        XmlNode node = el;
        while (node is XmlElement)
        {
            pathList.Add(node.Name);
            node = node.ParentNode;
        }
        pathList.Reverse();
        string[] nodeNames = pathList.ToArray();
        return String.Join("/", nodeNames);
    }

这甚至更容易

 ''' <summary>
    ''' Gets the full XPath of a single node.
    ''' </summary>
    ''' <param name="node"></param>
    ''' <returns></returns>
    ''' <remarks></remarks>
    Private Function GetXPath(ByVal node As Xml.XmlNode) As String
        Dim temp As String
        Dim sibling As Xml.XmlNode
        Dim previousSiblings As Integer = 1

        'I dont want to know that it was a generic document
        If node.Name = "#document" Then Return ""

        'Prime it
        sibling = node.PreviousSibling
        'Perculate up getting the count of all of this node's sibling before it.
        While sibling IsNot Nothing
            'Only count if the sibling has the same name as this node
            If sibling.Name = node.Name Then
                previousSiblings += 1
            End If
            sibling = sibling.PreviousSibling
        End While

        'Mark this node's index, if it has one
        ' Also mark the index to 1 or the default if it does have a sibling just no previous.
        temp = node.Name + IIf(previousSiblings > 0 OrElse node.NextSibling IsNot Nothing, "[" + previousSiblings.ToString() + "]", "").ToString()

        If node.ParentNode IsNot Nothing Then
            Return GetXPath(node.ParentNode) + "/" + temp
        End If

        Return temp
    End Function

 public static string GetFullPath(this XmlNode node)
        {
            if (node.ParentNode == null)
            {
                return "";
            }
            else
            {
                return $"{GetFullPath(node.ParentNode)}\\{node.ParentNode.Name}";
            }
        }