如何在列表中去除所有字符串中的空格

Question

我的列表是这样的：

mylist=[ " ","abc","bgt","llko","    ","hhyt","  ","      ","iuyt"]

如何移除列表中包含空格的所有字符串？

- no1

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你所说的“空”是指包含仅为空格的字符串吗？ - edsioufi

我的程序读取一个文件，将每一行分割开来，所以在列表中会有空字符串，也就是空格。 - no1

我不知道为什么没有人建议这个，但是以下代码似乎是所有答案中最快的 - [elem for elem in mylist if not elem.isspace()] - Sukrit Kalra

isspace()被支持了吗？我不知道... 谢谢你！ - no1

Answer 1

你可以使用列表推导式：list comprehension。

 new_list = [elem for elem in mylist if elem.strip()]

strip() 保证了即使字符串只包含多个空格，也会被删除。

- edsioufi

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或者只需使用[elem for elem in mylist if elem.strip()] - Joachim Isaksson

Answer 2

使用filter和未绑定方法str.strip。

Python 2.x

>>> mylist=[ " ","abc","bgt","llko"," ","hhyt"," "," ","iuyt"]
>>> filter(str.strip, mylist)
['abc', 'bgt', 'llko', 'hhyt', 'iuyt']

Python 3.x

>>> mylist=[ " ","abc","bgt","llko"," ","hhyt"," "," ","iuyt"]
>>> list(filter(str.strip, mylist))
['abc', 'bgt', 'llko', 'hhyt', 'iuyt']

- falsetru

Answer 3

只需使用过滤器和 None 参数即可。

filter(None, mylist)

如果“空字符串”指的是只包含空白字符的字符串，则应该使用以下代码：

filter(str.strip, mylist)

示例：

>>> filter(None, ['', 'abc', 'bgt', 'llko', '', 'hhyt', '', '', 'iuyt'])
['abc', 'bgt', 'llko', 'hhyt', 'iuyt']
>>> filter(str.strip, [' ', 'abc', 'bgt', 'llko', ' ', 'hhyt', ' ', ' ', 'iuyt'])
['abc', 'bgt', 'llko', 'hhyt', 'iuyt']

- Viktor Kerkez

Answer 4

尝试使用filter(lambda x: x.strip(), mylist)：

>>> mylist=[ " ","abc","bgt","llko"," ","hhyt"," "," ","iuyt"]
>>>
>>> filter(lambda x: x.strip(), mylist)
['abc', 'bgt', 'llko', 'hhyt', 'iuyt']
>>>
>>> mylist=[ " ","abc","bgt","llko","    ","hhyt","  ","      ","iuyt"]
>>>
>>> filter(lambda x: x.strip(), mylist)
['abc', 'bgt', 'llko', 'hhyt', 'iuyt']
>>>

- user1129665

Answer 5

mylist = [x for x in [ " ","abc","bgt","llko"," ","hhyt"," "," ","iuyt"] if x]

使用“if”子句的列表推导，而在这种情况下，依赖于Python在布尔上下文中将空字符串（和空容器）视为“False”的事实。

如果您所说的“空”是指长度为零或仅包含空格，则可以将if子句更改为if x.strip()

- Jim Dennis

Answer 6

我会这样做：

>>> mylist=[ " ","abc","bgt","llko"," ","hhyt"," "," ","iuyt"]
>>> new_list = [e for e in mylist if len(e.strip())!=0]
>>> new_list
      ['abc', 'bgt', 'llko', 'hhyt', 'iuyt']

- crs17

Answer 7

该方法isalpha()检查字符串是否只包含字母字符：

mylist=[ " ","abc","bgt","llko"," ","hhyt"," "," ","iuyt"] 
mylist = [word for word in mylist if word.isalpha()]
print mylist

Output:['abc', 'bgt', 'llko', 'hhyt', 'iuyt']

- badc0re

Answer 8

mylist = [s for s in mylist if str is not " "]

- Henrik

Answer 9

list = ["first", "", "second"]
[x for x in list if x]

输出：['第一个'，'第二个']

根据建议缩短，下面给出相同的问题

从字符串列表中删除空字符串

- kondapaka

Answer 10

>>> mylist=[ " ","abc","bgt","llko"," ","hhyt"," "," ","iuyt"]
>>> [i for i in mylist if i.strip() != '']
['abc', 'bgt', 'llko', 'hhyt', 'iuyt']

- Adem Öztaş