我正在尝试从C#应用程序调用一个Ant脚本。我希望控制台窗口弹出并保持开启状态(现在只是调用命令提示符,但最终我想调用一个可能需要长达一小时的Ant脚本)。以下是我使用的代码,它改自原始代码:
public void ExecuteCommandSync(object command)
{
try
{
// create the ProcessStartInfo using "cmd" as the program to be run,
// and "/c " as the parameters.
// Incidentally, /c tells cmd that we want it to execute the command that follows,
// and then exit.
System.Diagnostics.ProcessStartInfo procStartInfo =
new System.Diagnostics.ProcessStartInfo("cmd", "/k " + command);
// The following commands are needed to redirect the standard output.
// This means that it will be redirected to the Process.StandardOutput StreamReader.
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
// Do not create the black window.
procStartInfo.CreateNoWindow = false;
// Now we create a process, assign its ProcessStartInfo and start it
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo = procStartInfo;
proc.Start();
proc.WaitForExit();
}
catch (Exception objException)
{
Console.WriteLine(objException);
}
}
我希望能够传入最多5个参数,但现在我只关心能够让窗口保持足够长的时间以便查看正在发生的事情,并且我对由ant脚本生成的任何内容都不感兴趣。我不想要求任何人替我完成工作,但我已经困扰了一段时间,所以任何帮助将不胜感激!