如果我有这样一个列表:
>>> data = [(1,2),(40,2),(9,80)]
如何提取出两个列表 [1, 40, 9] 和 [2, 2, 80]?当然,我可以迭代并自己提取这些数字,但我猜肯定有更好的方法吧?
解压操作是:
In [1]: data = [(1,2),(40,2),(9,80)]
In [2]: zip(*data)
Out[2]: [(1, 40, 9), (2, 2, 80)]
编辑:您可以在赋值时分解生成的列表:
In [3]: first_elements, second_elements = zip(*data)
如果你真的需要列表作为结果:
In [4]: first_elements, second_elements = map(list, zip(*data))
zip(*data)
等同于
zip((1,2), (40,2), (9,80))
列表推导式拯救大局:
first = [x for (x,y) in data]
second = [y for (x,y) in data]
还有
In [1]: data = [(1,2),(40,2),(9,80)]
In [2]: x=map(None, *data)
Out[2]: [(1, 40, 9), (2, 2, 80)]
In [3]: map(None,*x)
Out[3]: [(1, 2), (40, 2), (9, 80)]